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lora16 [44]
3 years ago
10

In humans these organs are part of a lager system the ___ system?

Chemistry
2 answers:
trasher [3.6K]3 years ago
8 0

Answer:

B) digestive

Explanation:

Delicious77 [7]3 years ago
3 0

Answer:digestive

Explanation: i did this ans got it right

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Hitman42 [59]

Answer:

An ice pack uses friction and the chemicals inside make it mix to make it cold

Explanation:

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3 years ago
What is the net ionic equation for the precipitation reaction between BaCl2 and Na2So4? I know the answer ( Ba2+(aq) + SO42-(aq)
elixir [45]

Answer:

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

Explanation:

Chemical equation:

BaCl₂ +  Na₂SO₄   →   BaSO₄ + NaCl

Balanced Chemical equation:

BaCl₂(aq) +  Na₂SO₄(aq)   →   BaSO₄(s) + 2NaCl(aq)

Ionic equation:

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq)  →  BaSO₄(s)+ 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq)  →   BaSO₄(s)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

5 0
3 years ago
Most hottest month of the year<br><br><br>​
devlian [24]
Depends on where you live but generally speaking it is either June or July
7 0
3 years ago
Read 2 more answers
This is a natural Landmark can vary greatly in size as a result of flooding and evaporation what is its correct name and locatio
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4 0
3 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
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