Find the sum of the arithmetic series 7+13+...+601.

Mathematics

1 answer:

Juliette [100K]3 years ago

5 0

Answer:

Step-by-step explanation:

d=13-7=6

Let number of terms=n

l=a+(n-1)d

601=7+(n-1)6

601=7+6n-6

601=6n+1

6n=601-1=600

n=600/6=100

$s_{n}=\frac{n}{2} (a1+an)\\=\frac{100}{2}(7+601)\\=50 \times 608\\=30400$

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