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lubasha [3.4K]
3 years ago
14

A uniform stationary ladder of length L and mass M leans against a smooth vertical wall, while its bottom legs rest on a rough h

orizontal floor. The coefficient of static friction between floor and ladder is μ. The ladder makes an angle θ with respect to the floor. A painter of weight 1/2M stands on the ladder a distance d from its base.
Physics
1 answer:
ikadub [295]3 years ago
3 0

Answer:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

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Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

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The answer is:  " 208 g " .
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Explanation:
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The formula/ equation for density is:
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D = m / V  ;  That is,  "mass divided by volume" ;
 
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                   "mass per unit volume";  in which the "mass" is expressed in units of "g" ("grams") ;  and the "unit volume" is expressed in units of:
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           {Note the exact equivalent:  1 cm³ = 1 mL }.
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         →  The formula is:  " D = m / V "  ; 
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   in which:

     "D" refers to the "density" (see above), which is: "8.9 g/cm³ " (given); 

     "m" refers to the "mass" , in units of "g" (grams), which is unknown; and we want to find this value;
                 
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                 We want to find the mass, "m" ; so we take the original equation/formula for the density:
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             And we rearrange; to isolate "m" (mass) on ONE side of the    equation; and then we plug in our known/given values;
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