The corect answers will be:
1) A
2) B
3) D
Hope this helped :)
Based on the table and the equation of reaction; the
- rate of consumption of oxygen between time 20 and 40s is 0.005 M/s
- rate of consumption of oxygen between time 40 and 60s is 0.0025 M/s
<h3>What is rate of a reaction?</h3>
The rate of a reaction is the rate at which reactants molecules are consumed or products are formed.
- Rate of reaction = change in concentration of reactants or products/ time taken
Based on the equation of reaction, the rate of consumption of oxygen is equal to the rate of consumption of methane.
Thus. rate of consumption of oxygen from time 20 seconds to time 60 seconds is calculated as follows:
Rate between 20 and 40 = 1.0 - 0.9/20
- Rate of consumption of oxygen = 0.005 M/s
Rate between 40 and 60 = 0.9 - 0.85/20
- Rate of consumption of oxygen = 0.0025 M/s
Therefore, the rate of consumption of oxygen decreases with time.
Learn more about rate of reaction at: brainly.com/question/25724512
Answer:
See explanation
Explanation:
According to chemistry libretexts(2020); "The rms velocity is directly proportional to the square root of temperature and inversely proportional to the square root of molar mass. Thus quadrupling the temperature of a given gas doubles the rms velocity of the molecules. ... As the temperature of a gas is increased, the velocity of the molecules is also increased."
Hence considering two gases for which the Vrms of the particles of one is high and that of the other is low, we can conclude that the gas having the higher Vrms is at a higher temperature than the gas having a lower Vrms according to the foregoing.
2C4H10 + 13O2 = 8CO2 + 10H2O
1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10
2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O
3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
