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Xelga [282]
3 years ago
9

Inside stars in space, the nuclei of hydrogen atoms fuse together to form helium atoms. This represents which form of energy?

Chemistry
2 answers:
mixas84 [53]3 years ago
6 0

Explanation:

When two small nuclei combine together to form a large nuclei then it is known as nuclear fusion.

When nuclei of two hydrogen atoms fuse together then it results in the formation of a helium atom along with the release of lot of energy. This energy is nuclear energy.

This nuclear reaction is as follows.

      ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Thus, we can conclude that nuclear fusion represents nuclear energy.


Rina8888 [55]3 years ago
3 0
This is nuclear energy by fusion !!
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Why was the line of best fit method used to determine the experimental value of absolute zero?
BartSMP [9]

Answer:

<u><em></em></u>

  • <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>

Explanation:

Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.

                       \dfrac{V}{T}=k\\\\V=kT

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.

When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

Meaning that the Volume at 273.15ºC is zero.

You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.

3 0
3 years ago
The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that
kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is 1.1\times 10^6 M.

HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)

This value indicates that

A. CN^- is a stronger base than ONO^-

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is ONO^-

D. The conjugate acid of CN- is HCN

Answer: A. CN^- is a stronger base than ONO^-

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When K_{p}>1; the reaction is product favoured.

When K_{p}; ; the reaction is reactant favored.

When K_{p}=1; the reaction is in equilibrium.

As, K_p>>1, the reaction will be product favoured and as it is a acid base reaction where HONO acts as acid by donating H^+ ions and CN^- acts as base by accepting H^+

Thus HONO is a strong acid thus ONO^- will be a weak conjugate base and CN^- is a strong base which has weak HCN conjugate acid.

Thus the high value of K indicates that CN^- is a stronger base than ONO^-

7 0
2 years ago
How many dL in 1,000 mL
Anna007 [38]

1,000 mL is the same as 10 dL.

6 0
2 years ago
Read 2 more answers
For the following experiments, identify the independent variable and the dependent variable:
faust18 [17]

Answer:

A) IV: number of hours DV: score

Explanation:

Coz,

IV- is the variable that u change

DV- is the variable that u test or measure

In this case, we need to change the hours of studying to see how studying for different hours [1 hr, 2hr, etc (( Independant variable coz we're changing the no. of hours)) ] is going to affect the student's score, and in the end, we are measuring the score of each student [this is the dependant variable].

3 0
2 years ago
(PLEASE ANSWER + BRAINLIEST !!)
MatroZZZ [7]
A gamma ray has a mass and atomic number of 0 meaning it doesn’t effect the nucleus.
E.g
60 60 0
Co —> Co + gamma ray
27 27 0

7 0
3 years ago
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