Answer:
K = 8.1 x 10⁻³
Explanation:
We are told here that these gas phase reactions are both elementary processes, thus the reactions forward and reverse are both first order:
A→B Rate(forward) = k(forward) x [A]
and for
B→A Rate(reverse) = k(reverse) x [B]
At equilibrium we know the rates of the forward and reverse reaction are equal, so
k(forward) x [A] = k(reverse) x [B] for A(g)⇌B(g)
⇒ k(forward) / k(reverse) = [B] / [A] = K
4.7 x 10⁻³ s⁻1 / 5.8 x 10⁻¹ s⁻¹ = 8.1 x 10⁻³ = K
Notice how this answer is logical : the rate of the reverse reaction is greater than the forward reaction ( a factor of approximately 120 times) , and will be expecting a number for the equilibrium constant, K, smaller than one where the reactant concentration, [A], will prevail.
It is worth to mention that this is only valid for reactions which are single, elementary processes and not true for other equilibria.
During physical changes, matter always retains its chemical properties.
Answer:
6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation
Explanation:
Carbon, Oxygen, Hydrogen
Reactants are carbon dioxide and water, products are glucose and oxygen
Dynamic Equilibrium I have no idea about (soz)
I believe this might be endothermic
Carbon-Oxygen
We breathe in oxygen, we breathe out carbon dioxide.
Atomic number should be the answer