Select the lewis structure for xeo2f2 which correctly minimizes formal charges.
1 answer:
Answer:
explanation and image attached
Explanation:
Our aim is to draw a structure of XeO2F2 whith the least formal charges. We must remember that the compound has 34 valence electrons.
To obtain the least formal charges then Xe must have a total of twelve electrons on its valence shell instead of eight.
The other atoms around the central Xe atom are arranged as shown in the image attached.
Image Credit: UCLA
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