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3 years ago

What is chemistry?

Chemistry

1 answer:

kirill [66]3 years ago

3 0

Answer:the branch of science which examines the material of the universe and changes that these materials undergo

Chemistry deals with composition,structure,properties of matter and changes that these materials undergo

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A certain atom has a mass of 16 and an atomic number of 7. What element is this ?

snow_tiger [21]

Answer:

Nitrogen

Explanation:

According to the Periodic Table, the atom with a mass is 16 but the Atomic number is 7 for Nitrogen. That means that Nitrogen is an isotope.

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3 years ago

How many secondary (2°) carbons are found in 5-ethyl-3,3,4-trimethylheptane??

Gelneren [198K]

5-Ethyl-3,3,4-trimethylheptane has 3 secondary carbon. A primary carbon written as 1° is a carbon that has one carbon atom attached to it. A secondary carbon written as 2° is a carbon attached to two other carbons, while a tertiary carbon written as 3° is a carbon attached to three other carbons.

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3 years ago

Read 2 more answers

A sample of gas has an initial volume of 3.88 l at a pressure of 707 mmhg . part a if the volume of the gas is increased to 5.43

JulsSmile [24]

Using boyles law
p1v1=p2v2
v1=3.88
v2=5.43
p1=707
p2=?
707x3.88=p2x5.43
2743.16/5.43=p2
p2=505mmHg

4 0

3 years ago

a mixture containing 21.4 g of ice. (0.00 c) and 75.3 g of water (55.3 c) is placed in an insulatated container

Leto [7]

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7 0

3 years ago

Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of

shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

$2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}$

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

$70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}$

For the oxygen:

$81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}$

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

$\frac{0.81}{2}=0.41$

For the oxygen:

$\frac{2.54}{19}=0.13$

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

$81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}$

7 0

3 years ago

What is chemistry? ​

What is chemistry?