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DedPeter [7]
4 years ago
9

Help me for number 8 and 9

Chemistry
1 answer:
krek1111 [17]4 years ago
5 0
Both of the lizards have adapted by having their skin the same colour as their habitat so they could camouflage into the environment and not be spotted by predators.

the rabbit population would decrease as the rabbits would be unfamiliar with the new predators way of hunting so they wouldn't have adapted to be able to get away from the new predator
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Name the following alkyne: CH3CH₂C = CCH₂CH₂CH3
liubo4ka [24]

The given alkyne is Option A 3-heptyne

<h3>What is an Alkyne ?</h3>

The hydrocarbon having at least one C-C triple bond is called an Alkyne.

It has the general formula of   \rm C_n H_{2n+2} .

In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.

It has been asked in the question that

CH3CH₂C ≡  CCH₂CH₂CH3 is which alkyne from the given option.

The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .

To know more about Alkyne

brainly.com/question/23508203

#SPJ1

<h3 />

6 0
2 years ago
when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to blank k
Makovka662 [10]
Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.

For this problem, we will assume constant pressure. Based on the law:
(Volume/Temperatur)1 = (Volume/Temperature)2
(3.75/100) = (6.52/T)
T = 166.667 kelvin
4 0
3 years ago
Read 2 more answers
What is a rule for determining the atomic mass of an atom or ion ?
In-s [12.5K]

Answer:

Mass = Number of neutrons + Atomic number (aka number of protons)

Explanation:

4 0
3 years ago
HELP!!!!
Elan Coil [88]

Answer: 908 g Fe2O3

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that
svetlana [45]

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

6 0
3 years ago
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