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Lelu [443]
3 years ago
10

Many of the whales in the ocean rely upon tiny marine organisms, called plankton, for food. If all of the plankton suddenly died

, what might happen to the whales? A.
They would start eating fish.
B.
They would not survive either.
C.
They would go into hibernation.
D.
Nothing would change.
Physics
1 answer:
exis [7]3 years ago
8 0

Answer:

I believe the answer to be B.

Explanation:

Without food, the whales would die.

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An object is at rest in front of a compressed spring. It travels over a surface that exerts a kinetic frictional force on it and
PolarNik [594]

Answer:

the object will travel 0.66 meters before to stop.

Explanation:

Using the energy conservation theorem:

E_i+K_i+W_f=K_f+U_f

The work done by the friction force is given by:

W_f=F_f*d\\W_f=\µ*m*g*d\\W_f=0.35*4*9.81*d\\W_f=13.7d[J]

so:

\frac{1}{2}1800*(10*10^{-2})+0-13.7d=0+0\\d=0.66m

3 0
3 years ago
A body of mass 2.7 kg makes an elastic collision with another body at rest and continues to move in the original direction but w
kramer

Answer:

a)

1.35 kg

b)

2.67 ms⁻¹

Explanation:

a)

m_{1} = mass of first body = 2.7 kg

m_{2} = mass of second body = ?

v_{1i} = initial velocity of the first body before collision = v

v_{2i} = initial velocity of the second body before collision = 0 m/s

v_{1f} = final velocity of the first body after collision =

using conservation of momentum equation

m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}

Using conservation of kinetic energy

m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35

b)

m_{1} = mass of first body = 2.7 kg

m_{2} = mass of second body = 1.35 kg

v_{1i} = initial velocity of the first body before collision = 4 ms⁻¹

v_{2i} = initial velocity of the second body before collision = 0 m/s

Speed of the center of mass of two-body system is given as

v_{cm} = \frac{(m_{1} v_{1i} + m_{2} v_{2i})}{(m_{1} + m_{2})}\\v_{cm} = \frac{((2.7) (4) + (1.35) (0))}{(2.7 + 1.35)}\\\\v_{cm} = 2.67 ms⁻¹

8 0
3 years ago
I need help plz help me​
kirza4 [7]

Answer:ghhg

Explanation:

8 0
3 years ago
A golf ball has more mass than a tennis ball because it ____. (1 point) takes up more space. contains more matter. contains diff
Elis [28]
D.) Because it has a definite composition...
5 0
3 years ago
A piston above a liquid in a closed container has an area of 0.75m^2, and the piston carries a load of 200kg. What will be the e
seraphim [82]

Answer:

2613.3 pa

Explanation:

p=F/A

p=ma/A

p=200×9.8/0.75

p=2613.3

6 0
3 years ago
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