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3 years ago

As shown in the figure below, Cindy rushes 30 mtoward her truck. She notices she forgot her lunch and

Physics

1 answer:

kvasek [131]3 years ago

8 0

Answer:

A: 0 m/s I think

B: 1.5 m/s

Explanation:

If she returned to her starting position then she has covered no distance as far as velocity is concerned.

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when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in pa

liberstina [14]

Let R₁ and R₂ be the two Resistance

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

I = O.31A ( in series)

I = 1.6 A ( in parallel)

when two resistance connected in series

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω (equation1.)

When two resistance connected in parallel

$R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2} }$

V = I Rp

V= I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

(R₁ - R₂ ) ² = (38.70) ² - 4x 290.25

(R₁ - R₂ ) ² = 336.69 Ω

R₁ - R₂ = 18.34 (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω

Using the value of R₁ in equation 1 we get

R₂ = 38·700 - 28.535

RR₂ = 10.125 Ω

R₁ = 28. 535 v and R₂ 10.125 Ω

To know more about resistance in series and parallel:

brainly.com/question/27882579

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7 0

11 months ago

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 18.0t and y =

In-s [12.5K]

Position: x = 18t y = 4t - 4.9t²

First derivative: x' = 18 y' = 4 - 9.8t

Second derivative: x'' = 0 y'' = - 9.8

Position vector: P = (18t) i + (4t - 4.9t²) j

Velocity vector: V = (18) i + (4 - 9.8t) j

Acceleration vector A = (- 9.8) j

6 0

2 years ago

Read 2 more answers

In a basketball game, a player shoots a jump shot. Which force actually causes the player to jump? the player pushing down on th

Gemiola [76]

Answer: the player pushing down on the floor

Explanation:

4 0

2 years ago

Read 2 more answers

arlik [135]

2b2t hope that helps

5 0

2 years ago

A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a

Galina-37 [17]

Answer:

$E = (0.56 \times 10^8 ) r \ \ N/c$

Explanation:

Given that:

$\rho_o = (10^{-3} ) \ c/m^3$

R = (0.1) m

To find the electric field for r < R by using Gauss Law

${\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)$

For r < R

$Q_{enclosed}=(\rho) ( \pi r^2 ) l$

$E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}$

$E= \dfrac{\rho ( r)}{2 \varepsilon_o}$

where;

$\varepsilon_o = 8.85 \times 10^{-12}$

$E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}$

$E = (0.56 \times 10^8 ) r \ \ N/c$

4 0

2 years ago