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lilavasa [31]
3 years ago
15

A rectangle has a perimeter of 48 feet and a length of 14 feet. what equation can you solve to find the width?

Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0
14+14=28
48-28=20
20 divided by 2 =10
The width is 10
Elena-2011 [213]3 years ago
7 0

Answer:

2n+28=48

Step-by-step explanation:

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Someone help please!
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Answer:

9/10 I do this a lot

step-by-step explanation:

1/2 changes to 5/10 and 2/5 becomes 4/10 then you add and there is your answer

4 0
3 years ago
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A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 70 p
nikklg [1K]
X = large boxes and y = small boxes

x + y = 70.....x = 70 - y
60x + 65y = 4300

60(70 - y) + 65y = 4300
4200 - 60y + 65y = 4300
5y = 4300 - 4200
5y = 100
y = 100/5
y = 20 <=== the small boxes weigh 20 lbs

x + y = 70
x + 20 = 70
x = 70 - 20
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5 0
3 years ago
Is -10 -5 equal to -10+(-5)?Explain in terms of additive inversed.
laiz [17]
Yes because they both equal -15 because you actually turn -10+(-5) into a subtraction problem because if there's a + and -, you actually turn it into a minus and the answer is -15.  
4 0
3 years ago
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2. Mr. Andrew wants to give each of his students an equal number of the crayons he bought. There are 32 students in Mr. Andrew’s
Vladimir79 [104]

Answer:

Step-by-step explanation:

2.

Because we don't know how many crayons he bought we will call it c.

c = total number of crayons purchased

T = total number of crayons each student gets

To determine how many crayons each student gets we divide c by 32, because that's the number of students in his class.

c / 32 = T

So let's say he purchased 120 crayons.

c = 120

120/32 = T

T = 3.75

Since he can't give a fraction of a crayon, in this case, each student will get 3 crayons.

3.

We will now pretend there are 24 crayons in 1 box.

So T still equals the total number of crayons each student gets and c still equals number of crayons purchased, but now we also have b which equals the number of crayons in 1 box.

c = total number of crayons purchased

T = total number of crayons each student gets

b = number of crayons in 1 box

x = number of boxes purchased

So b*x = c

We can still write the equation:

c / 32 = T

We know T = 12 So we plug 12 in for T

c / 32 = 12  Now multiply each side by 32, so 32 will cancel on the left.

32c/32 = 12 * 32

c = 12 * 32

c = 384

So if he needs to purchase 384 crayons we can use our other equation.

b*x = c    

b = 24

c = 384

So we plug those in.

24x = 384  Divide each side by 24 so 24 will cancel on the left.

24x/24 = 384/24

x = 384/24

x = 16

So he needs to buy 16 boxes of crayons in this instance. We can figure out how many boxes he bought in #2 by using the same equation.

b*x = c  

c = 120 in #2

b =24

24 * x = 120

24x/24 = 120/24

x = 120/24

x = 5

So for each student to have 12 crayons he needs to purchase 11 more boxes (16 - 5 = 11).

This will work for whatever numbers you were given.

Remember:

c = total number of crayons purchased

T = total number of crayons each student gets

b = number of crayons in 1 box

x = number of boxes purchased

b*x = c

c / 32 = T

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3 years ago
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