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Xelga [282]
3 years ago
13

A long straight wire has fixed negative charge with a linear charge density of magnitude 4.6 nC/m. The wire is to be enclosed by

a coaxial, thin-walled, nonconducting cylindrical shell of radius 2.2 cm. The shell is to have positive charge on its outside surface with a surface charge density σ that makes the net external electric field is zero. Calculate σ.
Physics
1 answer:
Semmy [17]3 years ago
7 0

Answer: -33.3 * 10^9 C/m^2( nC/m^2)

Explanation: In order to solve this problem we have to use the gaussian law, the we have:

Eoutside =0 so teh Q inside==

the Q inside= 4.6 nC/m*L + σ *2*π*b*L where L is the large of the Gaussian surface and b the radius of the shell.

Then we simplify and get

σ= -4.6/(2*π*b)= -33.3 nC/m^2

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Answer:  \dfrac{d-0.5at^2}{t}=v_i

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These spectra are from the same element. Which is an emission spectrum, which an absorption spectrum?
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Answer:

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3 years ago
Just a thought
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Answer:

Explanation:

THE FOURTEEN WEEKS' COURSES

IN

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Fourteen Weeks iq Natural Philosophy,

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Fourteel Weeks iq Popular Geology,

Fourteeq Weeks iQ2 Human P1ysiology,

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Fourteeq Weeks iq Botany,

A Key, containing Answers to the Questions

and Problems in Steele's I4 Weeks' Courses,

4 1ISTORIC4L SERIES,

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Clanlbers' Elenments of Zoology,

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6 0
3 years ago
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FromTheMoon [43]
A=atomic mass 
Z=atomic number  (nº of protons).
N=neutons.

A=Z+N

Data:
A=39
Z=19

A=Z+N
39=19+N
N=39-19=20.

It therefore has 20 neutrons in its nucleus.
6 0
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