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Xelga [282]
2 years ago
13

A long straight wire has fixed negative charge with a linear charge density of magnitude 4.6 nC/m. The wire is to be enclosed by

a coaxial, thin-walled, nonconducting cylindrical shell of radius 2.2 cm. The shell is to have positive charge on its outside surface with a surface charge density σ that makes the net external electric field is zero. Calculate σ.
Physics
1 answer:
Semmy [17]2 years ago
7 0

Answer: -33.3 * 10^9 C/m^2( nC/m^2)

Explanation: In order to solve this problem we have to use the gaussian law, the we have:

Eoutside =0 so teh Q inside==

the Q inside= 4.6 nC/m*L + σ *2*π*b*L where L is the large of the Gaussian surface and b the radius of the shell.

Then we simplify and get

σ= -4.6/(2*π*b)= -33.3 nC/m^2

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Explanation:

Distance covered by the particle is given by:

Distance (d) = rate (v) × time (t)                

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Distance travelled by Jim, d₁ = (60t + 10)

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The distance between Mary and Jim is greater than or equal to 100 miles.

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10t\ge90

t\ge9\ h

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2 years ago
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3 years ago
An ice cube floats in a glass of water. will cold flow from ice into the water
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3 years ago
If Anya decides to make the star twice as massive, and not change the length of any crossbar or the location of any object, what
charle [14.2K]

Answer:

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JulsSmile [24]

Answer:

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Explanation:

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