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Rufina [12.5K]
3 years ago
15

I need help on this question

Chemistry
2 answers:
IRINA_888 [86]3 years ago
6 0
I think positive feedback
Deffense [45]3 years ago
5 0
B. I’m sorry if I’m wrong ! Wasn’t sure about this question .
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How many mL of 0.506 M HClare needed to dissolve 9.85 g of BaCO3?
Blababa [14]

Answer:

197mL of 0,506M HCl

Explanation:

The reaction of HCl + BaCO₃ is:

BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.

The moles of BaCO₃ in 9,85 g are:

9,85 g of BaCO₃ × \frac{1mol}{197,34 g} = <em>0,0499 moles of BaCO₃</em>

As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:

0,0499 moles of BaCO₃ × \frac{2molHCl}{1molBaCO_{3}} =<em> 0,0998 moles of HCl</em>

If you have a 0,506M HCl, you need to add:

0,0998 moles of HCl× \frac{1L}{0,506moles} = 0,197 L ≡ 197mL

I hope it helps!

8 0
2 years ago
Which of these experimental designs could lead to bias?
Lilit [14]
Hey there i see you need help well i am here to do just that it is c because if you are getting paid your more likely to lie ans say"great" things. 
hope this helps 
7 0
3 years ago
One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
The balanced chemical equation is written as:

<span>CsF(s) + XeF6(s) ------> CsXeF7(s)

We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride.  We calculate as follows:

11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
6 0
3 years ago
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Which of the following would be the best object for stirring hot liquids? (1 point)
MakcuM [25]
A Wooden Spoon is your answer because metal attracts heat more, so it would get hotter.

The wooden spoon would not, so you would use that.

Glad I could help, and good luck!

6 0
3 years ago
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Can someone help your amiga :(??
bekas [8.4K]

i think the answer is C but don't take my word for it

4 0
2 years ago
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