Ask question

Ask question

All categories

3 years ago

15

All of the following are features of karst topography EXCEPT sinkholes. Disappearing and emerging streams. Caverns. Continuous s

treams.

1 answer:

Minchanka [31]3 years ago

4 0

D, continuous streams.

You might be interested in

Which has more mass, a mole of water (H2O) or a mole of glucose (C6H12O6)? a. water b. glucose c. The masses are the same

riadik2000 [5.3K]

The correct answer is A

8 0

3 years ago

What is the oxidizing agent in galvanic cell?

ipn [44]

The ion in the cathode that gains electrons

7 0

3 years ago

How many moles of nitrogen trifluoride (NF3) can be produced from 9.65 mole of Fluorine gas (F2)

user100 [1]

Answer:

6.43 moles of NF₃.

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.

Thus, 6.43 moles of NF₃ were obtained from the reaction.

4 0

3 years ago

What causes a top to stop spinning?

lina2011 [118]

Tops stops spinning because it doesn't have energy or ran out of force for example when you spin a top you give force to it then after 30 sec it going to stop going slower and slower that Is losing energy that's how tops stops spinning

7 0

3 years ago

How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you

SOVA2 [1]

Explanation:

The given data is as follows.

Concentration of solution = 0.5 M

Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically, Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

Hence, calculate the number of moles as follows.

No. of moles = Molarity × Volume

= $0.5 M \times 1 L$

= 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

= $0.5 mol \times 132.119 g/mol$

= 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0

3 years ago