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mina [271]
3 years ago
10

A chemist prepares a solution of aluminum chloride (AlCl3) by measuring out 11 gr of aluminum chloride (AlCl3) into a 50 ml volu

metric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's aluminum chloride solution. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

1.6 M

Explanation:

To answer this question first we <u>calculate the molar mass of AlCl₃</u>, using the atomic weights of Al and Cl:

  • AlCl₃ ⇒ 27 g/mol + (35.45 g/mol)*3 = 133.35 g/mol

Now with the molar mass, and the mass weighed, we can <u>calculate mol AlCl₃</u>:

  • 11 g AlCl₃ ÷ 133.35 g/mol = 0.082 mol AlCl₃

Finally we <u>calculate concentration in mol/L</u>, keeping in mind that 50mL = 0.05 L:

  • 0.082 mol AlCl₃ / 0.05 L = 1.6 M
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