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mina [271]
3 years ago
10

A chemist prepares a solution of aluminum chloride (AlCl3) by measuring out 11 gr of aluminum chloride (AlCl3) into a 50 ml volu

metric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's aluminum chloride solution. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

1.6 M

Explanation:

To answer this question first we <u>calculate the molar mass of AlCl₃</u>, using the atomic weights of Al and Cl:

  • AlCl₃ ⇒ 27 g/mol + (35.45 g/mol)*3 = 133.35 g/mol

Now with the molar mass, and the mass weighed, we can <u>calculate mol AlCl₃</u>:

  • 11 g AlCl₃ ÷ 133.35 g/mol = 0.082 mol AlCl₃

Finally we <u>calculate concentration in mol/L</u>, keeping in mind that 50mL = 0.05 L:

  • 0.082 mol AlCl₃ / 0.05 L = 1.6 M
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Answer:

The number of mole of the unknown metal is 3.58×10¯³ mole

Explanation:

We'll begin by calculating the number of mole hydrogen gas, H2 that will occupy 80.3 mL at stp.

This is illustrated below:

Recall:

1 mole of any occupy 22.4L or 22400 mL at stp.

1 mole of H2 occupies 22400 mL at stp.

Therefore, Xmol of H2 will occupy 80.3 mL at stp i.e

Xmol of H2 = 80.3/22400

Xmol of H2 = 3.58×10¯³ mole

Therefore, 3.58×10¯³ mole of Hydrogen gas was released.

Now, we can determine the mole of the unknown metal as follow:

The balanced equation for the reaction is given below:

X + 2HCl —> XCl2 + H2

From the balanced equation above,

1 mole of the unknown metal reacted to produce 1 mole of H2.

Therefore, 3.58×10¯³ mole of the unknown metal will also react to produce 3.58×10¯³ mole of H2.

Therefore, the number of mole of the unknown compound is 3.58×10¯³ mole.

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3 years ago
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A dehydration reaction starting with 3.8 g cyclohexanol produces 2.6 g cyclohexene. Calculate the theoretical yield for this rea
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Answer:

Theoretical yield of C6H10 = 3.2 g.

Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

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Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

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Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

Theoretical yield of C6H10 = 3.2 g

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Answer:

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