I believe the correct answer is C) 30<span>°
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Answer: 4.089; 4.870; 4.881; 4.89
Answer:
12. 5(5x+4)(5x-4)
13. 2(4v+5)(4v-5)
14. 5(3x+2)(3x-2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
A dependent variable in an expression is one whose value can be determined only when the value of other variable (i.e independent) is known.
A. The cost at the fitness center depends on the number of months (x).
The cost is the dependent variable, and number of months (x) is the independent variable.
f(x) = 100 + 40x
Example, the cost paid for 12 months can be determined as;
f(12) = 100 + 40(12)
= 100 + 480
= 580
Thus, $580 would be paid for 12 months at the fitness center.
B. The lettuce is sold at $1.69 per pound. The cost depends on the number of pounds of lettuce bought.
The cost is the dependent variable, while the number of pounds of lettuce (x) bought is the independent variable.
So that;
f(x) = 1.69x
The cost of 10 pounds of lettuce can be determined as;
f(x) = 1.69(10)
= 16.9
Thus, the cost of 10 lb of lettuce is $16.90.
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
