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RSB [31]
3 years ago
5

Find the sum 2.75+(-2)+(5.25)

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

6 is the answer

Step-by-step explanation:

Hope I have helped.

liraira [26]3 years ago
4 0
2.75-2+5.25
= 6



I hope I helped !
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A fruit company delivers its fruit in two types of boxes: large and small. A delivery of
Tema [17]

Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

<em>Let weight of large box be l and small box be s.</em>

<em />

"<u>3 large boxes and  5 small boxes has a total weight of  116 kilograms</u>":

3l+5s=116

and

"<u>9 large boxes and  7 small boxes has a total weight of  238 kilograms</u>":

9l+7s=238

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>

<em>3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}</em>

<em>now,</em>

<em>9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75</em>

<em />

<em>now we plug in 13.75 into s into equation of l to find s:</em>

<em>l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75</em>

5 0
3 years ago
Formulate a rational algebraic equation of the problem​
liubo4ka [24]

Answer:

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5 0
2 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Joanne has a rectangular kitchen that is 10 ft by 15 ft. She decides to increase the length and the width by the same amount (x)
Elodia [21]

Answer:

NO

Step-by-step explanation:

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3 years ago
If a line has a slope of -4 and a u intercept of 1, which of the following is it's graph?
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Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
3 0
3 years ago
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