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3 years ago

What is the free-fall acceleration at the surface of the moon?

1 answer:

4 0

The acceleration due to gravity is 1.62m/s^2, this is because the moons gravity is 1/6th that of Earth's (9.81m/s^2) hope this helps! you could also use Newton's law of gravity, F=GM/R^2 where g is the universal gravitational constant, M= mass of the object and R=radius. There should be a neg sign in front of the equation since objects in free fall fall downwards from the given object. Hope this Helps........

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You and your dog go for a walk to the park. On the way, your dog takes many side trips to chase squirrels or examine fire hydran

Marysya12 [62]

Answer:

yes. We will have the same displacement.

Explanation:

It's in the definition of a displacement that " displacement is the change in position and if the initial and final position is same then the displacement will be zero". So in the park from starting position if we end up walking at the same position then our displacement will be zero because our initial and final positions are same.

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4 years ago

PLS HELP PHYSICS

Vika [28.1K]

Answer:

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3 years ago

Which is an example of transforming potential energy to kinetic energy? Select two options

blsea [12.9K]

Answer : 

.changing chemical energy to thermal energy

.changing nuclear energy to radiant energy

Explanation : 

<h3>Hope it helps you mate ))</h3>

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3 years ago

Where is the independent variable usually located in a scientific table? First column Second column Third through fifth columns

Reika [66]

Explanation:

On the horizontal side left side

4 0

3 years ago

An object with a mass of 32 kg has an initial energy of 500). At the end of the experimentthe velocity of the object is recorded

Alik [6]

Answer:

F = 1.68 N

Explanation:

Let's solve this exercise in parts.

Let's use the concept of conservation of the mechanical nerve

initial

Em₀ = 500 J

The energy is totally kinetic

Em₀ = K = ½ m v₀²

v₀ = $\sqrt{\frac{2 Em_{o} }{m} }$

v₀ = √ (2 500/32)

v₀ = 5.59 m / s

now with kinematics we can find a space

v² = v₀² - 2 a x

the negative sign is because the body is stopping

a = $( \frac{v_{o}^{2} - v^{2} }{2x} )$

let's calculate

a = (5.59² - 5.1²) / 2 50

a = 0.0524 m / s²

Finally let's use Newton's second law

F = ma

F = 32 0.0524

F = 1.68 N

7 0

3 years ago