All categories

3 years ago

What is 1+39? Greghyyuiyrsfffgghhhhhhju

Mathematics

1 answer:

MariettaO [177]3 years ago

4 0

Answer:

Step-by-step explanation:

The number after 39, or 39 plus one, is 40.

You might be interested in

A shopkeeper marks the price on articles 25% above the cost price. After allowing 10% discount, it was sold at gain of Rs 150. F

SashulF [63]

Answer: $Rs. 166.67$

Step-by-step explanation:

Given

Mark up price is 25% higher than cost price

The shopkeeper gives a discount of 10%

Suppose the cost price is $x$

Mark up price is $1.25x$

Selling price is

$\Rightarrow 1.25x\times 0.9=1.125x$

It is given Rs150

$\therefore 150=1.125x\\\Rightarrow x=\text{Rs}133.33$

Marked up price is $\text{Rs }166.67$

7 0

3 years ago

Write 433.38 in word form

Firdavs [7]

Four hundred thrity-three point thirty eight

Please put me as a Brainlier

8 0

4 years ago

Read 2 more answers

Help with number 22 plsssss

mario62 [17]

Answer:

192.972 mi/h

Step-by-step explanation:

To solve this, you have to add up all of the speeds and divide by how many values there are.

So if all of them are added together, it equals 771.888. Then, you divide this number by 4 to find the average. In this case, the average is 192.972mi/h.

3 0

3 years ago

Read 2 more answers

Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =

lara [203]

The domain and range of a function are the possible x and y values of the function.

The domain and the range of the function is: (a) $\mathbf{D:\{x \in R|x \ne -2,2\}}$ and $\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

The functions are given as:

$\mathbf{f(x) = \frac{4}{x^2 - 4}}$

$\mathbf{g(x) = x + 2}$

(g o f)(x) is calculated as:

$\mathbf{(g\ o\ f)(x) = g(f(x))}$

So, we have:

$\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}$

Take LCM

$\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }$

$\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$

Represent the denominator as follows, to calculate the domain

$\mathbf{x^2 - 4 \ne 0 }$

Add 4 to both sides

$\mathbf{x^2 \ne 4 }$

Take square roots of bot sides

$\mathbf{x \ne \±2 }$

Hence, the domain of the function is:

$\mathbf{D:\{x \in R|x \ne -2,2\}}$

On the graph of $\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$ (see attachment), the function does not have a value from y = 1 to 2.

Hence, the range is:

$\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

Read more about domain and range at:

brainly.com/question/1632425

5 0

2 years ago

Read 2 more answers

(c−9)2−(4c−2)2 factor

shutvik [7]

Answer:

−2(3c + 7)

Step-by-step explanation:

Factor the polyomial

5 0

3 years ago