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2 years ago

A rogue wave is a random monstrous wave that occurs unexpectedly in the ocean.

Physics

2 answers:

Tpy6a [65]2 years ago

8 0

A wave with a large amplitude

a wave check

natulia [17]2 years ago

8 0

Answer:

give the other man brainliest

Explanation:

he deserves it

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Help please!!!

TiliK225 [7]

Answer:

Cu 8.92

Explanation:

The formula for density is mass/volume. If you were to divide 62.44 by 7, you would get 8.92. Since copper is the only metal in this table that has a density of 8.92, that is the answer.

7 0

3 years ago

Please help me with the following question:

pishuonlain [190]

Answer: a. 667N

b. 665N

c. 54.5N

Explanation:

a) on the surface of the earth

W = mg

W = 68 × 9.81

= 667N

b) at the top of Everest (8848 m above sea level).

W =mg × R²/(R + H)²

W = 667 × [6378²/(6378 + 8.848)²

W = 665N

c) has 2 1/2 times the radius of the earth

W = mg × R²/(R + H)²

W = 667 × R²/(R + 2.5R)²

W = 54.5N

3 0

2 years ago

The distance versus this plot for a particular object shows a quadratic relationship. Which column of distance data is possible

SOVA2 [1]

Answer:

Explanation:

In Column A, the pattern is 1², 2², 3², etc. So x(t) = t², which is quadratic.

In Column B, the pattern is 2*1, 2*2, 2*3, etc. So x(t) = 2t, which is linear.

In Column C, the pattern is 9*1, 9*2, 9*3, etc. So x(t) = 9t, which is linear.

In Column D, the pattern is 1/1, 1/2, 1/3, etc. So x(t) = 1/t, which is reciprocal.

In Column E, the pattern is 1/1², 1/2², 1/3², etc. So x(t) = 1/t², which is reciprocal.

5 0

3 years ago

(An easy problem which will be graded). Later in the quarter we will spend some time solving the diffusion equation Op(r, t) = D

alexandr402 [8]

Answer:

Explanation:

Answer is in the attachment below:

7 0

3 years ago

The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doub

Fofino [41]

Answer:

F' = F

Explanation:

The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:

$F = \frac{Gm_1m_2}{r^2}$

where,

F = Force of attraction

G = Universal gravitational costant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

$F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}$

7 0

2 years ago