Question

A feverish student weighing 75,000 grams was immersed in 400,000 g of water at 4.0°C to try to reduce the fever. The student's body temperature dropped from 40.0°C to 37.0°C. Assuming the specific heat of the student to be 3.77 J/(g·°C), what was the final temperature of the water?

Answer 1

Heat lost = (75000)(3.77)(3) = 848250 J = heat gained by water

848250 = 400000(4.814)(T)
T = 0.507 C
4 + 0.507 = 4.507 C