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3 years ago

7

A feverish student weighing 75,000 grams was immersed in 400,000 g of water at 4.0°C to try to reduce the fever. The student's b

ody temperature dropped from 40.0°C to 37.0°C. Assuming the specific heat of the student to be 3.77 J/(g·°C), what was the final temperature of the water?

1 answer:

schepotkina [342]3 years ago

3 0

Heat lost = (75000)(3.77)(3) = 848250 J = heat gained by water

848250 = 400000(4.814)(T)
T = 0.507 C
4 + 0.507 = 4.507 C

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