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3 years ago

How is a gravitational field around an object shown

1 answer:

3 0

In physics, a gravitational field is a model used to explain the influence that a massive body extends into the space around itself, producing a force on another massive body. Thus, a gravitational field is used to explain gravitational phenomena, and is measured in newtons per kilogram (N/kg).

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Speed is the rate of change in

vaieri [72.5K]

Speed is the rate of change <span>of distance.</span>

6 0

3 years ago

Read 2 more answers

A person walks 2 miles every day to work, leaving her front porch at 7:00 A.M. and arriving at work at 7:30 A.M. ON the way home

Nataly [62]

Answer:

The displacement is zero miles

Explanation:

The displacement of an object that moves from point A to point B is defined as

$d =B-A$

Where d is the displacement of the object. The displacement does not depend on the trajectory of the object. It only depends on the linear distance between the end point and the starting point.

In this case we know that the person walks from home to work and then walks from work to home. Therefore, the total displacement is the linear distance between the point where its journey begins and the point where the route ends.

The tour begins on the front porch of your house and ends on the front porch of your house (when you return from work). If we call A to the front porch of the house then the displacement is:

$d = A-A = 0$

The displacement is zero miles, since the person finishes the journey just where it started (front porch)

7 0

2 years ago

A punter drops a 2.0 kg ball from rest vertically 1 meter down onto his foot. The ball leaves the foot with a speed of 18 m/s at

pav-90 [236]

Answer:

Explanation:

Given

mass of drop $m=2 kg$

height of fall $h=1 m$

ball leaves the foot with a speed of 18 m/s at an angle of $55^{\circ}$

Velocity of ball just before the collision with the floor

$u^=2gh$

$u=\sqrt{2gh}$

$u=\sqrt{2\times 9.8\times 1}=4.42 m/s$

Impulse delivered in Y direction

$J_y=m(v\sin (55)-(-u))$

$J_y=2(18\sin (55)+4.42)$

$J_y=38.32 kg-m/s$

Impulse in x direction

$J_x=m\times v\cos (55)$

$J_x=2\times 4.42\cos (55)=20.646$

$J_{net}=\sqrt{J_x^2+J_y^2}$

$J_{net}=\sqrt{(38.32)^2+(20.64)^2}$

$J_{net}=43.52 kg-m/s$

at an angle of $\tan \phi =\frac{J_y}{J_x}=\frac{38.32}{20.64}$

$\phi =tan^{-1}(1.856)$

$\phi =61.7^{\circ}$

7 0

2 years ago

If one oscillation has 5.8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?

vovikov84 [41]

If one oscillation has 5.8 times the energy of the second one of equal frequency and mass, 2.4:1 is the ratio of their amplitudes.

Oscillation is defined as the process of repeating fluctuations of a quantity or measure around its time equilibrium value. Oscillation can also be defined as the periodic fluctuation of matter between two values or about their average.

The definition of happiness is someone or something that makes you feel great joy or pleasure. An example of good luck is someone who wins the lottery. An example of happiness is a laughing baby. Besides making you feel better, positive emotions are good for your brain and body. It lowers stress hormones, relieves anxiety and depression, and strengthens the immune system. Feeling positive emotions every day has a huge impact on our well-being and health.

Learn more about oscillation here

brainly.com/question/12622728

#SPJ4

7 0

1 year ago

How long will it take for a car to accelerate to come to a stop if it is traveling at 20m/s and the car has a maximum decelerati

Pachacha [2.7K]

When the car comes to a stop, the final velocity must be 0 m/s.
Since the car js decelerating in a forward direction, acceleration must be negative.

final v = initial v + a•t
0 = 20 + (-6)t
t = 3.33s

5 0

3 years ago