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Rus_ich [418]
3 years ago
12

A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i

s 1.30 W. Assuming that the voltage remains constant, how much power is dissipated when the variable resistor is set to 532Ω? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.
Physics
1 answer:
mash [69]3 years ago
5 0

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance R_1=206ohm

Power dissipated in this resistance is P_1=1.30watt

Power dissipated in the resistor is equal to P=\frac{v_{rms}}^2{R}

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that \frac{P_1}{P_2}=\frac{R_2}{R_1}

\frac{1.3}{P_2}=\frac{532}{206}

P_2=0.503watt

So power dissipated in resistor 532 ohm is 0.503 watt  

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