The formula for the period of wave is: wave period is equals to 1 over the frequency.
![waveperiod=\frac{1}{frequency}](https://tex.z-dn.net/?f=%20waveperiod%3D%5Cfrac%7B1%7D%7Bfrequency%7D%20)
To get the value of period of wave you need to divide 1 by 200 Hz. However, beforehand, you have to convert 200 Hz to cycles per second. So that would be, 200 cyles per second or 200/s.
By then, you can start the computation by dividing 1 by 200/s. Since 200/s is in fractional form, you have to find its reciprocal form and multiply it to one which would give you 1 (one) second over 200. This would then lead us to the value
0.005 seconds as the wave period.
wave period= 1/200 Hz
Convert Hz to cycles per second first
200 Hz x 1/s= 200/second
Make 200/second as your divisor, so:
wave period= 1/ 200/s
get the reciprocal form of 200/s which is s/200
then you can start the actual computation:
wave period= 1 x s divided by 200
this would give us an answer of
0.005 s.
I think it's C, three hues that are adjacent on the color wheel
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,
![m_T = 25(7.7*10^4)Kg](https://tex.z-dn.net/?f=m_T%20%3D%2025%287.7%2A10%5E4%29Kg)
![m_T = 1.925*10^6Kg](https://tex.z-dn.net/?f=m_T%20%3D%201.925%2A10%5E6Kg)
Therefore the friction force at 29Km / h would be,
![f=250v](https://tex.z-dn.net/?f=f%3D250v)
![f= 250*29Km/h](https://tex.z-dn.net/?f=f%3D%20250%2A29Km%2Fh)
![f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})](https://tex.z-dn.net/?f=f%20%3D%20250%2A29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%29%28%5Cfrac%7B1h%7D%7B3600s%7D%29)
![f = 2013.889N](https://tex.z-dn.net/?f=f%20%3D%202013.889N)
In this way the tension exerts between first car and locomotive is,
![T=m_Ta+f](https://tex.z-dn.net/?f=T%3Dm_Ta%2Bf)
![T=(1.925*10^6)(0.2)+2013.889](https://tex.z-dn.net/?f=T%3D%281.925%2A10%5E6%29%280.2%29%2B2013.889)
![T= 3.8701*10^5N](https://tex.z-dn.net/?f=T%3D%203.8701%2A10%5E5N)
Therefore the tension in the coupling between the car and the locomotive is ![3.87*10^5N](https://tex.z-dn.net/?f=3.87%2A10%5E5N)
The correct answer is letter b.
To find the answer follow the following steps.
1. 6524.96 x .25 = X
2. 1631.24 = X
This works for all of the given answers to find the correct answer.