Answer:
1.Conduction
2.the second one
sorry if these are wrong
Step-by-step explanation:
Answer:
9
√
2
Step-by-step explanation:
1. Rewrite 162 as 
⋅2
2. factor 81 out of 162
3. Rewrite 81 as
4. Pull the terms from under the radical
![\sqrt[9]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B9%5D%7B2%7D)
I hope this helps :)
Answer:
Q1
cos 59° = x/16
x = 16 cos 59°
x = 8.24
Q2
BC is given 23 mi
Maybe AB is needed
AB = √34² + 23² = 41 (rounded)
Q3
BC² = AB² - AC²
BC = √(37² - 12²) = 35
Q4
Let the angle is x
cos x = 19/20
x = arccos (19/20)
x = 18.2° (rounded)
Q5
See attached
Added point D and segments AD and DC to help with calculation
BC² = BD² + DC² = (AB + AD)² + DC²
Find the length of added red segments
AD = AC cos 65° = 14 cos 65° = 5.9
DC = AC sin 65° = 14 sin 65° = 12.7
Now we can find the value of BC
BC² = (19 + 5.9)² + 12.7²
BC = √781.3
BC = 28.0 yd
All calculations are rounded
Answer:
27 degrees
Step-by-step explanation:
We are given that Angle AEF is 63. We can also see that EAF is a right angle. Since angles in a triangle add up to 180, we can use this to solve for AFE:
Angle AEF + EAF + AFE = 180
63 + 90 + AFE = 180
153 + AFE = 180
AFE = 27
<em>Or we can solve it another way</em>
Since EAF is a right angle, the other angles are complementary (they add up to 90) so...
Angle AEF + AFE = 90
63 + AFE = 90
AFE = 27
The opposite angles of a parallelogram are equal.
Therefore
m∠A = m∠C, so that
5y - 3 = 3y + 27
Subtract 3y from each side.
5y - 3y - 3 = 3y - 3y + 27
2y - 3 = 27
Add 3 to each side.
2y - 3 + 3 = 27 + 3
2y = 30
y = 30/2 = 15
Therefore
m∠A = 5*15 - 3 = 72°
m∠C = 72°
Let x = m∠B
Then x = , m∠B = m∠C
Because the sum of the angles in the parallelogram is 360°, therefore
x + x + 72 + 72 = 360
2x = 360-144 = 216
x = 216/2 = 108
Answer:
m∠A = 72°
m∠B = 108°
