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polet [3.4K]
3 years ago
7

If you give siri 0 cookies and she has 0 cookies but then gives you back a cookie where did she get the cookie from? if You and

her had 0 cookies ?
Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer:

Maybe she borrowed a cookie from somone? or maybe bought a cookie?

Alchen [17]3 years ago
7 0

Answer:

from space maybe.....,.................

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Xander purchased 10 equally priced DVDs online. He paid $250, which included shipping. Which statements are true? Mark all that
artcher [175]

Xander paid $25 per CD plus shipping.
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4 years ago
A transformation of AKLM results in AK'L'M'.
zysi [14]
Translation, Dilation
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In how many ways can the letter of word number taken two at a time
Nitella [24]

Answer:

So the number of ways of choosing two distinct letters at a time is (42)=6. We can then add the duplicate pairs which are O,O and N,N to give a total of 8 possible pairs.

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3 years ago
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A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers t
Thepotemich [5.8K]

Answer:

The probability that exactly 12 buyers would prefer green

=0.00555

Step-by-step explanation:

We are given that

p=50%=50/100=0.50

n=14

We have to find the probability that exactly 12 buyers would prefer green.

q=1-p

q=1-0.50=0.50

Using binomial distribution formula

P(X=x)=nC_r p^r q^{n-r}

P(x=12)=14C_{12}(0.50)^{12}(0.50)^{14-12}

P(x=12)=14C_{12}(0.50)^{12}(0.50)^2

P(x=12)=14C_{12}(0.50)^{14}

P(x=12)=\frac{14!}{12!2!}(0.50)^{14}

P(x=12)=\frac{14\times 13\times 12!}{12!2\times 1}(0.50)^{14}

P(x=12)=91\cdot (0.50)^{14}

P(x=12)=0.00555

Hence, the probability that exactly 12 buyers would prefer green

=0.00555

3 0
3 years ago
A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken
Leviafan [203]

Answer:

a. H0:μ1≥μ2

Ha:μ1<μ2

b. t=-3.076

c. Rejection region=[tcalculated<−1.717]

Reject H0

Step-by-step explanation:

a)

As the score for group 1 is lower than group 2,

Null hypothesis: H0:μ1≥μ2

Alternative hypothesis: H1:μ1<μ2

b) t test statistic for equal variances

t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}

t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}

t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]

t=-3.076

c. α=0.05, df=22

t(0.05,22)=-1.717

The rejection region is t calculated<t critical value

t<-1.717

We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.

7 0
4 years ago
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