Question

There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting earth satellite
If the arm is 6.00 m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is 4.8x10^22 kg and its diameter is 3138 km .

Answer 1

Answer:

4.44586579653 rpm

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Europa = $4.8\times 10^{22}\ kg$

R = Radius of Europa = $\dfrac{3138000}{2}\ m$

r = Radius of arm = 6 m

$\omega$ = Angular velocity

Acceleration due to gravity is given by

$a=\dfrac{GM}{R^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 4.8\times 10^{22}}{\left(\dfrac{3138000}{2}\right)^2}\\\Rightarrow a=1.30053242374\ m/s^2$

Now, equating the above value with the motion of the arm

$a=\omega^2 r\\\Rightarrow \omega=\sqrt{\dfrac{a}{r}}\\\Rightarrow \omega=\sqrt{\dfrac{1.30053242374}{6}}\\\Rightarrow \omega=0.465569977508\ rad/s$

Converting to rpm

$0.465569977508\times\dfrac{60}{2\pi}=4.44586579653\ rpm$

The angular speed of the arm is 4.44586579653 rpm