A car with an initial speed of 4.30 m/s accelerates at a rate of 3 ms^2. What is the car's speed after 5 s?
1 answer:
You might be interested in
Explanation:
Given that,
Average power of sun
We need to calculate the intensity of light at Earth's position
Using formula of intensity
Where, I = intensity
P = power
Put the value into the formula
So, The intensity is 1347.616 W/m².
(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully reflective
Put the value into the formula
(B). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully absorptive
Hence, This is the required solution.
Answer:
x = 11.23 m
Explanation:
For this interesting exercise, we must use angular kinematics, linear kinematics and the relationship between angular and linear quantities.
Let's reduce to SI system units
θ = 155 rev (2pi rad / rev) = 310π rad
α = 2.00rev / s2 (2pi rad / 1 rev) = 4π rad / s²
Let's look for the angular velocity at the time the piece is released, with starting from rest the initial angular velocity is zero (wo = 0)
w² = w₀² + 2 α θ
w =√ 2 α θ
w = √(2 4pi 310pi)
w = 156.45 rad / s
The relationship between angular and linear velocity
v = w r
v = 156.45 0.175
v = 27.38 m / s
In this part we have the linear speed and the height that it travels to reach the floor, so with the projectile launch equations we can find the time it takes to arrive
y = t - ½ g t²
As it leaves the highest point its speed is horizontal
y = 0 - ½ g t²
t = √ (-2y / g)
t = √ (-2 (-0.820) /9.8)
t = 0.41 s
With this time we calculate the horizontal distance, because the constant horizontal speed
x = vox t
x = 27.38 0.41
x = 11.23 m