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Nimfa-mama [501]
3 years ago
9

A car with an initial speed of 4.30 m/s accelerates at a rate of 3 ms^2. What is the car's speed after 5 s?

Physics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

v = u + at

u = 4.30 m/s

a = 3 m/s^2

t = 5 s

v = 4.30 + (3)(5)

v = 4.30 + 15

v = 19.30 m/s

Explanation:

Hope this helps!

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The displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function :
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The maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.

<h3>What is simple harmonic motion?</h3>

Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side.

Simple Harmonic Motion

The given equation of the simple harmonic motion is

x=3.5 sin (\frac{\pi }{2t} + \frac{5\pi }{4} )

Data;

ω = π/2

k = 1.254N/m

Solving this

\frac{dx}{dt} = -3.5 X \frac{\pi }{2} cos (\frac{x\pi t}{2}+\frac{5\pi }{4}  )

Let's calculate the maximum velocity.

V_{m} =\frac{3.5\pi }{2}

This is only possible when cos θ = -1

The maximum kinetic energy is

K_m =\frac{1}{2} mv^2 = \frac{1}{2} X \frac{500}{1000} X \frac{7^2\pi ^2}^{4} ^2

w^2 = \frac{k}{m} \\k = w^2m\\k = \frac{\pi ^2}{4} X \frac{500}{1000} \\k =1.254 N/m

Using the value of spring constant, we can find the maximum potential energy.

P.E =\frac{1}{2} k x^2\\P.E =\frac{1}{2} X 1.234 X 3.5^2 \\P.E = 7.56 J

The maximum potential energy is 7.56J

The maximum mechanical energy is equal to the sum of maximum potential energy and the maximum kinetic energy.

ME = K.E + P.E

ME = 7.56J

From the calculations above, the maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.

Learn more on simple harmonic motion here;

brainly.com/question/15556430

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a foul ball is hit into the stands at a baseball game. the ball rises to a height of 38 meters and is caught on its way down by
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The velocity of the ball when it was caught is 12.52 m/s.

<em>"Your question is not complete it seems to be missing the following, information"</em>,

find the velocity of the ball when it was caught.

The given parameters;

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height above the ground where the ball was caught, h = 30 m

The height traveled by the ball when it was caught is calculated as follows;

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y = 38 - 30 = 8 m

The velocity of the ball when it was caught is calculated as;

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