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alexgriva [62]
3 years ago
14

With what allotrope of oxygen is it isoelectronic in NO2- ?

Chemistry
1 answer:
Ivahew [28]3 years ago
8 0
<span>Answer: O₃
</span><span />

<span>Explanation:
</span>
<span /><span /><span>
The term isoelectronic means same number of electrons.
</span><span />

<span>Then you need to count the number of electrons in the given species NO₂⁻.
</span><span />

<span>You have to count the number of electrons of N (nitrogen) atoms, the number of electrons of two O (oxygen) atoms, and the adjust for the negative charge of the ions.


</span><span>The atomic number of N is 7, meaning that each atom has 7 protons and 7 electrons.</span>
<span /><span>
The atomic number of O is 8, meaning that each atom has 8 protons and 8 electrons.
</span><span />

<span>The negative charge of the ion means that it has one extra electron, which is the responsible for the negative charge.
</span><span />

<span>Therefore the total number of electrons of the ion NO₂⁻ is 7 + 2 (8) + 1 = 24.
</span><span />

<span>Note that that 24 = 3 x 8, so 24 is the number of electrons in 3 atoms of oxygen.
</span><span />

<span>The moleucle O₃ is an allotrope of the oxygen. (an allotrope is a a form of an element with different structure and physical properties in the same physical state).
</span><span />

<span>Therefore, the allotrope of oxygen isoelectronic with NO₂⁻ is O₃ (ozone)</span>
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A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use
LekaFEV [45]

The empirical formula of this compound is H_2SO_4

<u>Given the following data:</u>

  • Percentage of H = 2.00%
  • Percentage of S = 32.7%
  • Percentage of O = 65.3%

<u>Scientific data:</u>

  • Molar mass of hydrogen (H) = 1.0 g/mol.
  • Molar mass of sulfur (S) = 32 g/mol.
  • Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

  • Mass of hydrogen (H) = 2.00 grams
  • Mass of sulfur (S) = 32.7 grams
  • Mass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

Number\;of\;moles = \frac{mass}{molar\;mass}

<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>

Number\;of\;moles = \frac{2.00}{1}

Number of moles = 2.0 moles

<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>

Number\;of\;moles = \frac{32.7}{32}

Number of moles = 1.0 moles

<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>

Number\;of\;moles = \frac{65.3}{16}

Number of moles = 4.0 moles

Empirical formula = H_2SO_4

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The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

Explanation:

Given data:

Energy of photon = 1.10 × 10⁻¹³ J.

Wavelength of photon = ?

Solution:

Formula:

E = h.c / λ

λ  = h. c / E

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λ  = 18.071 × 10⁻⁴ nm

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