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GenaCL600 [577]
2 years ago
15

a fitness club requires a $75 Initiation fee and dues of $25 per month write an expression for the cost of the membership for n

months​
Mathematics
1 answer:
sasho [114]2 years ago
3 0
75 + (25 x n) is the answer.
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Solve 2x + 5y = −13 3x − 4y = −8
zlopas [31]
If you would like to solve 2x + 5y = -13 and 3x - 4y = -8, you can do this using the following steps:

2x + 5y = -13       /*4
3x - 4y = -8         /*5
_______________
8x + 20y = -52
15x - 20y = -40
_______________
8x + 15x + 20y - 20y = -52 - 40
23x = -92
x = -92 / 23
x = -4

<span>3x - 4y = -8 
</span>3 * (-4) - 4y = -8
-12 - 4y = -8
12 + 4y = 8
4y = 8 -12
4y = -4
y = -1

The correct result would be x = -4 and y = -1.
6 0
2 years ago
Drag the operations into the order in which they should be performed to evaluate the expression below. 7 × 6 ÷ ( 13 − 10 ) + 4 a
monitta

Answer:It's 18

Step-by-step explanation:Multiply 7 and 6 to get 42

Subtract 10 from 13 to get 3

Divide 42 by 3 to get 14

Add 14 and 4 to get 18

5 0
2 years ago
Read 2 more answers
Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below. (0, -2) and
BaLLatris [955]

Answer:

y = -(5/2)x -2

Explanation:

The general formula for a straight line is y – mx + b.

The image below shows the graph of the line.

Step 1. <em>Calculate the slope</em>.

Slope = m = Δy/Δx = (y₂-y₁)/(x₂-x₁)

x₁ = 0; y₁ = -2

x₂ = -2; y₂ = 3     Calculate m

m = [3-(-2)]/(-2-0)

m = (3+2)/(-2)

m = 5/(-2)

m = -5/2

Step 2. <em>Calculate the y-intercept </em>

When x = 0, y = 2.

The y-intercept (b) is at y = -2

Step 3. <em>Write the equation </em>for the graph

y = mx + b

y = -(5/2)x - 2

3 0
2 years ago
Read 2 more answers
Find the measure Of PR
Misha Larkins [42]

Answer:

18

Step-by-step explanation:

The formula for this is a x b = c x d where a is SR, b is FR, c is QR and d is PR. This will give us the equation 9(16) = 8(5x + 8); 144 = 40x + 64; 80 = 40x; x = 2. Now, plug this into PR which will be 5(2)+8 = 18. This is your answer.

3 0
2 years ago
What is not a problem modular division is used for?
Oksana_A [137]

Answer:

First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.

Now, the modular division is the division in modular arithmetic.

Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.

4 0
3 years ago
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