<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
Answer:
add area of p' gram and ️.
(20 x 16) + ( .5 x 20 x 8)
Answer:
The answer to your question is D 64
Step-by-step explanation:
hope this helps you have a wonderful day.
Answer
42
Because that angle is 90 degrees so 90-48-42
Divide both sides by -2
-2(2x-1)=3x+16
distribute
-4x+2=3x+16
add 4x to both sides
2=7x+16
minus 16 from both sides
-14=7x
divide both sides by 7
-2=x
