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3 years ago

If the midpoint of two points is (2,5) and one of the endpoints is (6,3), what is the other endpoint?

Mathematics

1 answer:

aleksley [76]3 years ago

6 0

To answer this question, you need to draw out the graph first. By doing so, you will be able to know where the other endpoint is located. (Fig. 1)

Next, count the number from the midpoint to the endpoint to determine the coordinates for the other endpoint. (Fig. 2)
Example: From (2, 5) to (6, 3)
x: 2 to 6 = 4 steps
y: 5 to 3 = 2 steps

From there, you can determine the other endpoint like this.
Example: From (2, 5) to the other endpoint
x: 2 to x1 = 4 steps
y: 5 to y1 = 2 steps

Therefore, x1 = -2 and y1 = 7
Other endpoint: (-2, 7)

Sorry for the messy drawing, it is hard to draw without a pen. Haha... hope this helps :)

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The diameter of a circle is 3.2 meters. Which is the circumference of the circle rounded to the nearest hundredth of a meter?

Paraphin [41]

Answer:

10.05 meters

Step-by-step explanation:

If the diameter is 3.2 meters, then the radius is 1.6 meters.

Use the circumference formula, C = 2 $\pi$ r, and solve for C

C = 2 $\pi$ r

C = 2 $\pi$ (1.6)

C = 3.2 $\pi$

C = 10.05

So, to the nearest hundredth of a meter, the circumference is 10.05 meters

4 0

2 years ago

Find the value of x.

erastovalidia [21]

Answer:

60 = x

Step-by-step explanation:

180-144 = 36

36+84 = 120

180-120 = 60

7 0

2 years ago

Read 2 more answers

Explain how you know which method you should use to solve a rational equation.

notsponge [240]

<u>Methods to solve rational equation:</u>

Rational equation:

A rational equation is an equation containing at least one rational expression.

Method 1:

The method for solving rational equations is to rewrite the rational expressions in terms of a common denominator. Then, since we know the numerators are equal, we can solve for the variable.

For example,

$\frac{1}{2}=\frac{x}{2}\Rightarrow x=1$

This can be used for rational equations with polynomials too.

For example,

$\frac{1+x}{x-3}=\frac{4}{x-3}\Rightarrow(1+x)=4 \Rightarrow x=3$

When the terms in a rational equation have unlike denominators, solving the equation will be as follows

$\frac{x+2}{8}=\frac{3}{4}$

$\Rightarrow\frac{x+2}{1}=\frac{3\times8}{4}\Rightarrow{x+2}=2\times3$

$\Rightarrow{x+2}=6\Rightarrow x=6-2\Rightarrow x=4$

Method 2:

Another way of solving the above equation is by finding least common denominator (LCD)

$\frac{x+2}{8}=\frac{3}{4}$

Factors of 4: $1\times2\times2$

Factors of 8: $1\times2\times2\times2$

The LCD of 4 and 8 is 8. So, we have to make the right hand side denominator as 8. This is done by the following step,

$\Rightarrow\frac{x+2}{8}=\frac{3}{4}\times{2}{2}$

we get,

$\Rightarrow\frac{x+2}{8}=\frac{6}{8}$

On cancelling 8 on both sides we get,

$\Rightarrow(x+2)=6\rightarrow x=6-2\rightarrow x=4$

Hence, these are the ways to solve a rational equation.

7 0

2 years ago

A fruit company sells two types of boxes large and small. A delivery of two large boxes and three small boxes has a total weight

lara31 [8.8K]

Answer:

the large box weight is 6.50 kg and the small box weight is 13.75 kg

Step-by-step explanation:

The computation of each type of box weight is as follows:

Let us assume the large box be x

And, the small box be y

So,

2x + 3y = 47.......(i)

6x + 5y = 115........(ii)

Multiply by 3 in equation 1

6x + 9y = 141

6x + 5y = 115

Now subtract the last equation from the above one

4y = 26

y = 6.50

For x, it would be

2x+ 3(6.50) = 47

2x + 19.5 = 47

2x = 47 - 19.50

2x = 27.50

x = 13.75

Hence, the large box weight is 6.50 kg and the small box weight is 13.75 kg

4 0

2 years ago

The sum of three numbers is 9.The sum of twice the first number, 4times the second number, and 5times the third number is 25.T

Karo-lina-s [1.5K]

Answer:

x = 6, y = 2, z = 1

Step-by-step explanation:

This is a system of 3 equations with 3 unknowns. We need to first write the equations given the information and then solve them.

The first equation is the sum of 3 numbers, all unknown, is 9:

x + y + z = 9

The second equation is again a sum:

2x + 4y + 5z = 25

The third equation is the difference of only the first 2 numbers:

6x - y = 34

We will start with that last equation and solve it for y:

-y = -6x + 34 so

y = 6x - 34

Now we will go back to the first 2 equations and sub that 6x-34 in for each y. The first equation then becomes:

x + 6x - 34 + z = 9 and 7x + z = 43

The second equation then becomes:

2x + 4(6x - 34) + 5z = 25 and 26x + 5z = 161

We will solve those 2 bold equations by addition/elimination:

7x + z = 43

26x + 5z = 161

Multiply the first equation through by -5 to get rid of the z's. That equation then becomes:

-35x - 5z = -215

26x + 5z = 161

Adding straight down the columns gives you

-9x = -54 so

x = 6

Now we can plug that x value of 6 into any equation that has an x in it:

26(6) + 5z = 161 and

156 + 5z = 161 and

5z = 5 so

z = 1.

We can use the x value only again in the equation we solved for y in the beginning:

y = 6(6) - 34 so

y = 36 - 34 and

y = 2

The solution to this system in coordinate form is

(6, 2, 1)

5 0

3 years ago