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3 years ago

Consider the free-body diagram. If you want the box to move, the force applied while dragging must be greater than the

Physics

1 answer:

In-s [12.5K]3 years ago

8 0

the answer to this qustion is c friction force

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You and your roommate are moving to a city360 mi away. Your roommate drives a rental truck at a constant 50 mi/h , and you drive

AnnyKZ [126]

Answer:

42 minutes

Explanation:

First, let us find out the time required by the roommate, who is driving the truck, to reach the city.

We know that,

$time=\frac{distance}{speed} =\frac{360}{50} hrs=7.2hrs$

Now, you are planning to rest a bit after traveling for an hour. So,

distance covered in that 1 hour = $60mi/h\times1h=60 miles$

time required by you to cover the total distance = $\frac{360mi}{60mi/h} =6hours$

If you wish reach at the destination half an hour (0.5 h) before your roommate, you can expend a total of $7.2-0.5=6.7hours$ throughout your journey.

Hence, you can rest for $6.7-6=0.7hours=(0.7\times60)minutes=42minutes$

3 0

3 years ago

To determine the y-component of a projectile’s velocity, what operation is performed on the angle of the launch?

koban [17]

To determine the y component of velocity of a projectile sine operation is performed on the angle of launch.

Answer: sine

Explanation:

Thus $a_x=0,a_y=g$

The initial velocity u can be resolved along two directions.

Along the X direction initial velocity = u cos θ

Along y direction initial velocity= u sin θ

From the equation of motion $v= u+at$

Thus velocity along x direction $v_x$ =u cos θ

Velocity along y direction $v_y$ = u sinθ -gt

Sign of g is negative.

3 0

3 years ago

Read 2 more answers

What do you think Jose’s grandmother meant by saying that the bread was too dense? What other things can you think of that are “

Deffense [45]

The bread was most likely heavy

8 0

3 years ago

two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n

Alex_Xolod [135]

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, $F_A=450\ N$

Force applied by Team B, $F_B=415\ N$

We need to find the net force acting on the rope. It is equal to :

$F_{net}=F_A-F_B$

$F_{net}=450-415$

$F_{net}=35\ N$

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

4 0

3 years ago

The graph shows that the molecules in a liquid do not all have the same speed

amm1812

1. I don't see a graph
2. It could be because a liquid could be evaporating in the process
3. It could be that the liquid is getting colder
4. 1 liquid is medium and moving a the normal pace

8 0

4 years ago