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bixtya [17]
3 years ago
10

two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n

. what is the net force on the rope and what is its direction?
Physics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, F_A=450\ N

Force applied by Team B, F_B=415\ N

We need to find the net force acting on the rope. It is equal to :

F_{net}=F_A-F_B

F_{net}=450-415

F_{net}=35\ N

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

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An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach
matrenka [14]

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, \theta=60^{\circ}

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m

So, the maximum height reached by the object is 34.43 m.

6 0
3 years ago
When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai
geniusboy [140]

Answer:

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Explanation:

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P=\frac{W}{\Delta t}

Remember average work is average force (F) times displacement (Δs):

P=\frac{F \Delta s}{\Delta t}

but displacement over time is average speed v=\frac{\Delta s}{\Delta t}, then:

P=Fv (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

F=\frac{P}{v}

Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308\frac{m}{h} = 62.5 \frac{m}{s}, then:

F=\frac{22380}{62.5}=358.0 N

6 0
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the answer to you question is D.

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