1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_tiger [21]
3 years ago
9

Which best compares kinetic energy and temperature?

Physics
1 answer:
Zinaida [17]3 years ago
3 0

Temperature is directly proportional to the average kinetic energy of the molecules in a substance. If the degree of motion of the molecules inside an object doubles, the temperature will also double. Hope this helps. Have a nice day.

<span> </span>
You might be interested in
A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff, A second rock is thrown
Tcecarenko [31]

Answer:

12.25m/s

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since the initial velocity of the dropped rock is 0, you can write this as:

d=\dfrac{1}{2}(9.8)(3)^2=44.1m

Now, you can set up the equation for the thrown rock:

44.1=v_o(2)+\dfrac{1}{2}(9.8)(2)^2 \\\\\\44.1=2v_o+19.6 \\\\\\2v_o=24.5 \\\\\\v_o=12.25m/s

Hope this helps!

3 0
3 years ago
What does Newton's first law of motion tell us about velocity?
zubka84 [21]
Every body continues in a state of rest or uniform motion in a straight line unless acted on by a resultant external force. That's approximately Newton's first law of motion. 
So, the velocity of something tends to remain the same, unless an external force changes it. This is sometimes called "inertia". A body at rest, as in with "no velocity" will tend to remain at rest, unless there's a force on it. inertia again.
6 0
3 years ago
HELP PLEASEEEEEEEEEEE
sertanlavr [38]

Answer:

dolphins and wolfs very easy

Explanation:

7 0
3 years ago
Select the star life cycle that is accurate.
Veseljchak [2.6K]

Answer:

B according to the picture

Explanation:

Star of 3 stellar masses => red supergiant=>supernova=>neutron star

8 0
3 years ago
The current through a 10 ohm resistor is 1.2 amperes.What is the potential difference across the resistor?
Natalija [7]

<u>Answer</u>: The potential difference across the resistor is 12 volts.

<u>Explanation:</u>

To calculate the potential difference cross the resistor, we use Ohm's Law. This law states that the potential difference across two wires is directly proportional to the current flowing through that wire.

Mathematically,

V\propto I\\V=IR

Where,

V = potential difference = ?V

I = Current flowing = 1.2 A

R = Resistor = 10\Omega

Putting values in above equation, we get:

V=1.2\times 10=12V

Hence, the potential difference across the resistor is 12 volts

6 0
3 years ago
Other questions:
  • Which side of continents have a colder climate than might be expected?
    9·2 answers
  • What role will robots play in our future?
    11·2 answers
  • What is the velocity of a car that travels 100 meters north in for seconds
    8·2 answers
  • Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
    9·1 answer
  • A motorbike accelerates from rest at 12m/s in 3s on a level road. If the force is 3000n what is the total mass of the cyclist an
    14·2 answers
  • As she was trying to study, Tanisha asked her roommate to lower the radio. Her roommate had turned the radio up originally from
    7·1 answer
  • An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c
    15·1 answer
  • When the current in a toroidal solenoid is changing at a rate of 0.0200 A/s, the magnitude of the induced emf is 12.7 mV. When t
    5·1 answer
  • A disk, initially rotating at 120 rpm, is slowed down with a constant acceleration of magnitude 4 rad s2. If the disk has diamet
    15·1 answer
  • A trapeze artist swings in simple harmonic motion with a period of 3.8 s.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!