Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
Answer:
The wavelength is 3500 nm.
Explanation:
d= 
n= 1
θ= 30°
λ= unknown
Solution:
d sinθ = nλ
λ = 
λ = 3500 nm
Any object that is given any initial velocity and which follows a path due to gravitational force acting on it and by the frictional resistance of the atmosphere is called a projectile. This is because the object is projected and not influenced by anything except gravity.
Answer:
The coefficient of static friction between the coin and the turntable is 0.51
Explanation:
at the time of the slip:
centripetal force = frictional force
mv^2/r = x*m*980
v^2/r = 980x
x = v^2/980r
= [(120)^2]/[980*29]
= 0.51
Therefore, The coefficient of static friction between the coin and the turntable is 0.51
Answer: 15.6 metres
Explanation:
Given that:
length of wave (λ)= ?
Frequency of wave F = 28 Hertz
Speed of wave (V) = 437 m/s
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.
So, apply V = F λ
Make λ the subject formula
λ = V / F
λ = 437 m/s / 28 Hertz
λ = 15.6 m
Thus, the length of the wave is 15.6 metres