We know that the energy required to raise the temperature of a substance is the product of that substance's mass, specific heat capacity and the change in temperature. Mathematically:
Q = m * Cp * delta(T)
The Cp of water in Kcal/(kg*K) or Kcal/(kg*C) is 1. (Per unit Celsius and per unit Kelvin are interchangeable because one degree change in Celsius is equal to one degree change in Kelvin)
Using the formula,
Q = 0.5 * 1 * (50-20)
Q = 15 Kcal
Answer:
<u>18000 J</u> is the work can do by the motor.
Explanation:
If an electric motor works for 12 seconds and the power output is 1.5 KW = 1500 Watts we need to find how much work can an electric motor does.
We know that,
“Power” is defined as the “rate” of doing “work”, the “energy” transferred or converted per unit time. Mathematically, 
Where, units of power is “Watt”, units of work is “Joule” and time in “seconds”.
Substitute the given values to find work

1500 × 12 = work
Work = 18000 Joules
Therefore, work can done by an electric motor is <u>18000 J</u>.
Answer:
B)
Explanation:
a brilliant work on all the principles it open up a whole new world and change the world algebraicly
Making a model helps the scientists have a better example or view of what they are working with