Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Mole is the unit of amount of substances of specified elementary entities
According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation
n =pV/RT
Here given data is volume = 87.1 liters
Temperature = 74 °C means 347.15 k
Pressure = 3.5 atm
R = 0.0821
Putting this value in ideal gas equation then
n =pV/RT
n = 3.5 atm×87.1 liters / 0.0821 ×347.15 k
n = 021.65 mole
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
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Answer:
84.63924
Explanation:
one moles equals 40.30440
Hello!
How many molecules are in 30 liters of methane (CH4) at STP ?
We have the following information:
Knowing that by Avogadro's Law for each mole of substance we have 6.02 * 10²³ molecules, it is known that in STP (Standard Temperature and Pressure) one mole of any gas equals 22.4 L, then:
22.4 L ----------------- 6.02*10²³ molecules
30 L -------------------- y molecules

multiply the means by the extremes




Answer:
8.0625*10²³ molecules of methane
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Nuclear fission is the breakup of an atom and Nulcear fusion is the combination of two (or more, but almost always two) atoms to form a new atom.
Answer:
4.31 × 10²
Explanation:
Equation of the reaction;
⇌ 
The ICE Table is shown as follows:
⇌ 
Initial 3.10 2.50 0
Change - x -x + 2x
Equilibrium (3.10 - x) 0.0800 2x
From
;
We can see that 2.50 - x = 0.0800
So; we can solve for x;
x = 2.50 - 0.0800
x = 2.42
which = (3.10 -x) will be :
= 3.10 - 2.42
= 0.68
= 2x
= 2 (2.42)
= 4.84
![K_c = \frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)


430.62
≅ 431
= 4.31 × 10²