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Nonamiya [84]
3 years ago
14

How many moles are in 2.98x10^23 particles?

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 0.495 \ mol}}

Explanation:

We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

The units of particles cancel.

2.98*10^{23}  *\frac { 1 \ mol }{6.022*10^{23 } }}

\frac { 2.98*10^{23}}{6.022*10^{23 } }}  \ mol

0.4948522086 \ mol

<h3>2. Round</h3>

The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.

For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

0.495 \ mol

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

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Answer:

an organ system  Is a group of organs that work together to perform a com

Explanation:

that is the answer organ system

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5 0
3 years ago
A sample compound with a molar mass of 34.00g/mol is found to consist of 0.44g H and 6.92g O. Calculate both empirical and molec
balu736 [363]

Answer:

E.F= OH

M.F=O_{2} H_{2}

Explanation:

Empirical Formula

Step 1: Calculate mols of each element

0.44gH(1 mol H/ 1.008g H)= 0.4365 mol H

*note leave extra sig figs for calculations

6.92gO(1 mol O/ 16 g O)=0.4325 mol O

Step 2: Identify which is the smallest mol

*in this case 0.4365 mol H> 0.4325 mol O so we will use 0.4325 mol O

Step 3: Divide above calculations by the smallest mol

0.4325 mol O/0.4325= 1

0.4365 mol H/0.4325= 1.009 *rounds to 1

Step 4: use calculations as subscripts

Oxygen = 1 so the subscript will 1 (O)

Hydrogen = 1 so the subscript will 1 (H)

making E.F= OH

Molecular Formula:

Step 1: identify  molecular mass and mass from the E.F

the molecular mass is given 34.00g/mol

the mass of the E.F is

(oxygen mass from periodic table)+(hydrogen mass from periodic table)

16+1.008= 17.008

Step 2:Divide the molecular mass by the mass given by the emipirical formula.

\frac{34.00}{17.008}= 1.999 round to 2

Step 3:Multiply the empirical formula (the subscripts) by this number to get the molecular formula.  ANSWER: M.F=2(OH)- O_{2} H_{2}

3 0
3 years ago
Karl likes to use cruise control when he drives on
Yanka [14]

Answer:

3.96 MINUTES

Explanation:

Karl likes to use cruise control when he drives on

the highway. After setting cruise control at 33.53

m/s (75 mph). At this speed, how long would it

take Karl to travel 8 kilometers?

VELOCITY = DISTANCE/TIME

OR

V=D/T

SO

VT=D

SO

T=D/V

THE DISTANCE IS 8 KM

THE VELOCITY IS 75 MPH

THERE ARE 1.61 KM PER MILE

SO

75M[H =

75 X 1.61 KM/H =

121 KM/HR

T=D/V

T=8/121 =0.066 HOUR =

0.066 X 60 MINUTES =

3.96 MINUTES

CHECK

75 MPH =

(75 X 1.61) KM/60 MINUTES =

120,75 KM/60 MINUTES=

2.01 KM/MINUTE

to travel 8 K,M WILL TAKE

8/2.01 = 3.98 minutes

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School Math. Homework.
Ksju [112]

Answer:

The answer is TRUE!!!

Explanation:

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Why is it harder to remove an electron from fluorine than from carbon, or, to put it another way, why are the valence electrons
AlladinOne [14]

Answer:

5. The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly.

Explanation:

Both fluorine and carbon are located in the second period of the periodic table, it means that they have 2 shells, so the valence electrons are found at about the same distance from their respective nuclei.

But fluorine has a higher atomic number, 9, than the carbon, 6. The atomic number represents how many protons there are in the nucleus, then there are more protons (positive charge) at the fluorine nucleus, and because of that, the attraction force between the nucleus and the valence electron is stronger in fluorine.

If the force is stronger, it will be necessary more energy to break the bond, so it will be harder to remove an electron from fluorine than from carbon.

5 0
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