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vovangra [49]
3 years ago
13

What is the speed of sound in air at 40°C? 355 m/s 307 m/s 331 m/s 239 m/s

Physics
2 answers:
Iteru [2.4K]3 years ago
5 0

the answer is 355 m/s

Vikki [24]3 years ago
3 0
<span>This is not a good answer, because some one t o forgot to tell us the important temperature, and the given atmospheric pressure "at sea level" makes really no sense. In SI units with dry air at 20°C (68°F), the speed of sound c is 343 meters per second (m/s).</span>
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It was once recorded that a Jaguar
Artyom0805 [142]

Answer:

71.85 m/s

Explanation:

Given the following :

Length of skid marks left by jaguar (s) = 290 m

Skidding Acceleration (a) = - 8.90m/s²

Final velocity of jaguar (v) = 0

Speed of Jaguar before it Began to skid =?

Hence, initial speed of jaguar could be obtained using the formula :

v² = u² + 2as

Where

v = final speed of jaguar ; u = initial speed of jaguar(before it Began to skid) ; a = acceleration of jaguar ; s = distance /length of skid marks left by jaguar

0² = u² + (2 × (-8.90) × 290)

0 = u² + (-5,162)

u² = 5162

Take the square root of both sides

u = √5162

u = 71.847 m/s

u = 71.85m/s

6 0
3 years ago
What are the only elements that exist in nature as isolated atoms
agasfer [191]

Answer:

The only such elements are the Noble Gases (He, Ne, Ar, Kr, Xe, Rn)

(that is helium, neon, argon, krypton, xenon and radon)

Term: Monoatomic

Explanation:

6 0
3 years ago
A vehicle that goes from 5m/s to 45m/s in 8s. what is its acceleration?
GaryK [48]

Answer: 5m/s^2

Explanation:

V= 45m/s

U = 5m/s

t = 8s

a =?

V = u + at

45 = 5 + 8a

8a = 45 — 5

8a = 40

a = 40 / 8

a = 5m/s^2

3 0
3 years ago
A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40º and fly ano
Kobotan [32]

Wildlife researcher starts from a and then reaches b, he turns towards north 40 degree to move towards c.

Total displacement is ac

Total horizontal displacement = 4+4 cos40 =7.06 km

Total vertical displacement = 4 sin40 =2.57 km

Total displacement = \sqrt{7.06^2+2.57^2} = 7.51 km

7 0
3 years ago
An electron is brought from rest infinitely far away to rest at point P located at a distance of 0.041 m from a fixed charge q.
torisob [31]

Answer:

The electric potential in volts is 1.618 x 10⁻¹⁷ V

Explanation:

The electric potential, in volts, at point P, can be calculated as follow;

Electric potential is the work done in moving a unit positive charge from infinity to a particular point in the electric field.

Thus, the work done in this process in moving the charge to point p is 101eV.

Convert this Volts = 101 × 1.602 x 10⁻¹⁹ V

                              = 1.618 x 10⁻¹⁷ V

Therefore, the electric potential in volts is 1.618 x 10⁻¹⁷ V

3 0
3 years ago
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