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Sliva [168]
2 years ago
12

the threshold of hearing is defined as the minimum discernible intensity of the sound. it is approximately 10−12w/m2 . find the

distance d from the car at which the sound from the stereo can still be discerned. assume that the windows are rolled down and that each speaker actually produces 0.06 w of sound, as suggested in the last follow-up comment.
Physics
1 answer:
vivado [14]2 years ago
3 0

The distance is 97720.5 m

From the question, we have

P = 0.06 W × 2 = 0.12 W

d = ?

Sound intensity, I = P/4πd²

I = 10⁻¹² W/m²

10⁻¹² = 0.12/4πd²

d = 97720.5 m

The distance is 97720.5 m

Sound intensity :

The power carried by sound waves per unit area in the direction  perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. Sound intensity is a measure of how quickly energy moves across a given space. The unit area in the SI measurement system is 1 m2. So Watts per square meter are used to measure sound intensity. As there will be energy flow in certain directions but not in others, sound intensity also provides a measure of direction.

To learn more about Sound intensity visit: brainly.com/question/12899113

#SPJ4

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The force of attraction which exists between all objects with mass Is called
mafiozo [28]

Answer:

gravity

Explanation:

Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. It is an attraction that exists between all objects, everywhere in the universe. ... where G is called the Gravitational Constant.

7 0
3 years ago
Read 2 more answers
A block of iron at 33.0°C has mass 2.30 kg. If 3.50×104 J of heat are transferred to the block, what is its resulting temperatur
spayn [35]

Answer:

66.8°C

Explanation:

dQ = m*cp*dT where:

m = mass of block

cp = specific heat of iron

dT = temperature change

-------

dQ = 3.5 10^4 J

cp = 0.45 Kj / Kg = 450 J / Kg

3.5 10^4 = 2.3 * 450 * dt-----dt = 35000 / 450 * 2.3 = 33.8 °

-------

Final temperature = 33 + 33.8 = 66.8 °C

3 0
3 years ago
Relative to the ground, what is the gravitational potential energy of 68 kg
Kisachek [45]

Answer:

Explanation:

p.E=mgh

P.E=68*10*443

p.E=301240j

8 0
2 years ago
Vectors A and B lie in the xy ‑plane. Vector A has a magnitude of 17.1 and is at an angle of 150.5∘ counterclockwise from the +x
IRINA_888 [86]

Answer:

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

B = -25.41 i ^ -12.0 j ^ + 0 k ^

Explanation:

For this exercise let's use trigonometry by decomposing to vectors

vector A

module 17.1 with an angle of 150.5 counterclockwise.

         Sin 150.5 = A_{y} / A

         cos 150.5 = Ax / A

         A_{y} = A sin 150.5 = 17.1 sin 150.5

         Aₓ = A cos 1505 = 172 cos 150.5

         A_{y} = 8,420

         Aₓ = -14.870

the vector is

          A = -14.87 i ^ + 8.42 j ^ + 0 k ^

Vector B

         B_{y} = 28.1 sin 205.3

         Bₓ = 28.1 cos 205.3

         B_{y} = -12.009

          Bₓ = -25.405

the vector is

          B = -25.41 i ^ -12.0 j ^ + 0 k ^

5 0
3 years ago
Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.
77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0
2 years ago
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