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3 years ago

What are the only elements that exist in nature as isolated atoms

Physics

1 answer:

agasfer [191]3 years ago

6 0

Answer:

The only such elements are the Noble Gases (He, Ne, Ar, Kr, Xe, Rn)

(that is helium, neon, argon, krypton, xenon and radon)

Term: Monoatomic

Explanation:

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What is the total resistance of a 6 ohm and a 8 ohm resistor connected in series? (1 Point)

Oksanka [162]

Answer:

Total Resistance in circuit is Fourteen Ohms (14 Ω).

Explanation:

How do we know, if the resistors are connected in series, the total resistance is the sum of all the resistors.

(Important: The total resistance can only be added just when the resistors are connected in series)

Then, total resistance (TR ) is the sum of all resistors (T1 + T2, in this case)

TR = T1 + T2

According to problem data, we have:

TR = 8 Ω + 6 Ω

TR = 14 Ω

║Sincerely, ChizuruChan║

4 0

3 years ago

A parallel-plate capacitor in air has a plate separation of 1.31 cm and a plate area of 25.0 cm2. The plates are charged to a po

morpeh [17]

Answer:

a) before immersion

C = εA/d = (8.85e-12)(25e-4)/(1.31e-2) = 1.68e-12 F

q = CV = (1.68e-12)(255) = 4.28e-10 C

b) after immersion

q = 4.28e-10 C

Because the capacitor was disconnected before it was immersed, the charge remains the same.

c)*at 20° C

C = κεA/d = (80.4*)(8.85e-12)(25e-4)/(1.31e-2) = 5.62e-10 F

V = q/C = 4.28e-10 C/5.62e-10 C = 0.76 V

U(i) = (1/2)CV^2 = (1/2)(1.68e-12)(255)^2 = 5.46e-8 J

U(f) = (1/2)(5.62e-10)(0.76)^2 = 1.62e-10 J

ΔU = 1.62e-10 J - 5.46e-8 J = -3.84e-8 J

8 0

3 years ago

According to the law of conservation of mass, what is the mass of water

DENIUS [597]

Answer:

according to the conservation of mass,

according to the conservation of mass,the mass of the water is 36.04grams 

Explanation:

Hope It Help you

3 0

3 years ago

Read 2 more answers

An object 10mm in height is located 20cm from a crown glass spherical surface whose power is +10.00DS. Locate the image

Tasya [4]

The image is present at 20cm from the crown glass spherical surface.

To find the answer, we need to know about the lens formula.

<h3>What's the lens formula?</h3>

It's (1/V)-(1/U)= (1/f)
V= image distance from the lens, U= object distance, f= focal length of the lens

<h3>What's the image distance, if object is present at 20cm from crown glass of power 10DS?</h3>

Focal length (f)= 1/ power = 1/10 = 0.1 m
U= -20cm = -0.2m (-ve sign due to sign convection)
(1/V)-(-1/0.2)= (1/0.1)

=> (1/V)+5=10

=> 1/V= 5

=> V=0.2m = 20cm

Thus, we can conclude that the image is present at 20cm.

Learn more about the lens formula here:

brainly.com/question/2098689

#SPJ1

7 0

2 years ago

A stereo speaker is rated at P1000 = 52 W of output at 1000 Hz. At 20 Hz, the sound intensity level LaTeX: \betaβ decreases by 1

baherus [9]

Answer:

The value of the power is $P_c = 38.55 \ W$

Explanation:

From the question we are told that

The power rating $P_{1000} =P_b= 52 \ W$

The frequency is $f = 1000 \ Hz$

The frequency at which the sound intensity decreases $f_k = 20 \ Hz$

The decrease in intensity is by $\beta = 1.3 dB$

Generally the initial intensity of the speaker is mathematically represented as

$\beta_1 = 10 log_{10} [\frac{P_b}{P_a} ]$

Generally the intensity of the speaker after it has been decreased is

$\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]$

$\beta_1-\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]$

=> $\beta = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3$

=> $\beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3$

=> $\beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3$

=> $10log_{10} [\frac{P_b}{P_c} ] = 1.3$

=> $log_{10} [\frac{P_b}{P_c} ] = 0.13$

taking atilog of both sides

$[\frac{P_b}{P_c} ] = 10^{0.13}$

=> $[\frac{52}{P_c} ] = 10^{0.13}$

=> $P_c = \frac{52}{1.34896}$

=> $P_c = 38.55 \ W$

3 0

3 years ago