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3 years ago

A 1,200 kg car is accelerated at 3.7 m/s2. What force was needed to produce this acceleration?

Physics

2 answers:

Mashutka [201]3 years ago

4 0

The answer would be A

kondaur [170]3 years ago

3 0

Answer:

A. 4,440 N

Explanation:

A Force applied on an object with mass 'm' can change its velocity in a unit time. This change is called acceleration.

If a force 'F' is applied on a body of mass 'm', it produces an acceleration 'a' in the body.

Force is give as :

F = ma

In our case,

m = 1200 kg a = 3.7 m/s²

F = 1200 x 3.7

F = 4440 kgm/s²

F = 4440 N

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Is it correct to say that constant speed = 0 acceleration = no resultant force?

stepan [7]

Nope......... Constant speed but change in direction can cause acceleration which would give a finite force........

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3 years ago

A 2.0 kg puck is at rest on a level table. It is pushed straight north with a constant force of 5N for 1.50 s and then let go. H

lukranit [14]

Answer:

d = 6.32 m

Explanation:

Given that,

The mass of a puck, m = 2 kg

It is pushed straight north with a constant force of 5N for 1.50 s and then let go.

We need to find the distance covered by the puck when move from rest in 2.25 s.

We know that,

F = ma

$a=\dfrac{F}{m}\\\\a=\dfrac{5}{2}\\\\a=2.5\ m/s^2$

Let d is the distance moved in 2.25 s. Using second equation of motion,

$d=ut+\dfrac{1}{2}at^2\\\\d=0+\dfrac{1}{2}\times 2.5\times (2.25)^2\\\\d=6.32\ m$

So, it will move 6.32 m from rest in 2.25 seconds.

4 0

2 years ago

Pressure is always measured in comparison to a standard pressure.<br> True<br> False

irakobra [83]

Answer:

true

Explanation:

8 0

2 years ago

Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t

n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

$y=\frac{\lambda (m+\frac{1}{2})D}{d}$

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light used

In this problem we have:

$\lambda=683 nm = 683\cdot 10^{-9} m$ is the wavelength of the light

$d=1.1 mm = 0.0011 m$ is the width of the slit

m = 13 is the order of the minimum

$y=8.57 cm = 0.0857 m$ is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

$D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m$

6 0

3 years ago

Which planet has a moon with many sulfur volcanoes?

Murljashka [212]

Jupiter i hope it is right answer

6 0

2 years ago