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aniked [119]
3 years ago
8

Some people believe that the Moon’s phases are caused by Earth’s shadows on the Moon. Is this true? Use your model to explain.

Chemistry
1 answer:
Kisachek [45]3 years ago
5 0

<u>Answer:</u>   False

<em>Some people believe that the Moon’s phases are caused by Earth’s shadows on the Moon is false.</em>

<u>Explanation:</u>

<em>Some people believe that the Moon’s phases are caused by Earth’s shadows on the Moon is their misconception. </em>

The phases depend on its place relative with sun and earth.The phases of moon are new moon,waxing crescent, first quarter, waxing gibbon, full moon, wanning gibbon,last quarter, wanning crescent,new moon.

<em>For example, </em>

When<em> moon, earth, and sun</em> are exactly in the same line and moon lies in between earth and sun, the sun illuminates the back part of the moon which is not visible from earth. <em>This forms new moon</em>.

<em>So only relative positions matter in the phases of moon. </em>

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For the reaction
s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

Given parameters:

Molar mass of SO₃ = 80.0632g/mol

Mass of S = 17.9g

Molar mass of S = 32.065g/mol

Number of moles of O₂ = 0.157mole

Molar mass of O₂ = 31.9988g/mol

Unknown:

Maximum amount of SO₃

Solution

  We need to write the proper reaction equation.

           2S + 3O₂ → 2SO₃

We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.

So we simply compare the molar relationship between sulfur and product formed to solve the problem:

First, find the number of moles of Sulfur, S:

   Number of moles of S = \frac{mass }{molar mass}

   Number of moles of S =  \frac{17.9 }{32.065} = 0.558mole

Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:

       2 mole of Sulfur produced 2 mole of SO₃

   Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃

5 0
3 years ago
The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachlorid
stepladder [879]

Answer:

Final Answer: boiling point and high

Explanation:

3 0
3 years ago
Read 2 more answers
Select the correct answer.
matrenka [14]

Answer:

At equilibrium the rate of the forward reaction is equal to the rate of the backward reaction.

When the product of a reaction at equilibrium is increased the equilibrium will shift left or to the reactant side. As a result the excess product will get converted to reactant. This is in accordance to Le Chatelier's principle.

Le Chatelier's principle states that when a system is subjected to stress the equilibrium will shift in a direction to minimize effect of the stress.

Thus the products added to the system at equilibrium will make the equilibrium shift to the reactant side, the rate of the reverse or backward reaction will increase.

Explanation:

Hope This Helps Amigo!

5 0
3 years ago
Assume that instead of Taq polymerase, another polymerase, one that is very heat-sensitive, was used in a PCR. What differences
frez [133]

Answer:

Taq polymerase is a thermostable which states that it can even work at higher temperature. The main function of using this enzyme is that it is used to amplify the DNA which will help in producing ample amount of DNA sample.

The enzyme activity is temperature dependent. The denaturation and annealing steps of the PCR occurs at very high temperature.

Any other enzyme used at such an high temperature would have decreased the enzyme activity and the procedure would not be completed.

7 0
3 years ago
(a) The student dissolves the entire impure sample of CuSO4(s) in enough distilled water to make 100.mL of solution. Then the st
Talja [164]

Answer:

Explanation:

Given parameters :

Volume of solution  = 100mL

Absorbance of solution  = 0.30

Unknown:

Concentration of CuSO₄ in the solution = ?

Solution:

There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.

A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.

The concentration is 0.15M

Also, we can use:  Beer-Lambert's law;

                    A  = ε mC l

where εm is the molar extinction coefficient

             C is the concentration

             l is the path length

Since the εm is not given and assuming path length is 1;

         Then we solve for the concentration.

3 0
3 years ago
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