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kompoz [17]
3 years ago
5

Which extraction procedure will completely separate an amide from the by-product of the reaction between an amine and excess car

boxylic acid anhydride?
Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer: A. Add 0.1M NaOH to quench unreacted anhydride. Then add diethyl ether to separate the layers. The amide can be obtained from the ether layer by evaporating the solvent.

The options are

A) Add 0.1 M NaOH to quench unreacted anhydride. Then add diethyl ether and separate the layers. The amid e can be obtained from the ether layer by evaporating the solvent

B) Add 0.1M Hal to quench unreacted anhydride. Then add diethyl ether and separate the layers. The amide can be obtained from the ether layer by evaporating the solvent.

C) Add 0.1M NaOH to quench unreacted anyhyride. Then add diethyl ether and separate the layers. The amide can be obtained from the aqueous layer by neutralizing with HCl.

Explanation:

Extraction with aqueous base will hydrolyze and extract both the acidic carboxylic acid and the excess unreacted starting material to the aqueous layer, leaving the neutral amide in the ether layer.

DedPeter [7]3 years ago
4 0

Answer: You question seems not to be complete.

Complete Question:

Which extraction procedure will completely separate an amide from the by-product of the reaction between an amine and excess carboxylic acid anhydride?

A) Add 0.1 M NaOH to quench unreacted anhydride. Then add diethyl ether and separate the layers. The amid e can be obtained from the ether layer by evaporating the solvent

B) Add 0.1M Hal to quench unreacted anhydride. Then add diethyl ether and separate the layers. The amide can be obtained from the ether layer by evaporating the solvent.

C)Add 0.1M NaOH to quench unreacted anyhyride. Then add diethyl ether and separate the layers. The amide can be obtained from the aqueous layer by neutralizing with HCl.

Explanation:The extraction procedure to use is A.

Add 0.1 M NaOH to quench unreacted anhydride. Then add diethyl ether and separate the layers. The amide can be obtained from the ether layer by evaporating the solvent

This is because the byproduct of the reaction would give an acidic carboxylic acid and unreacted starting material would also be acidic. Therefore, Extraction with aqueous base is necessary which will hydrolyze and extract both of these into the aqueous layer, leaving the neutral amide in the ether layer.

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Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0
4 years ago
Does anyone know how to do this ??
lord [1]

Answer:

Look at your periodic table

Explanation:

It tells you everything like Potasium 1 and 1 ox and 1 hydrogen

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