Answer:
KO is the limiting reactant.
0.11 mol O₂ will be produced.
Explanation:
4 KO₂ + 2 H₂O ⇒ 4 KOH + 3 O₂
Find the limiting reagent by dividing the moles of the reactant by the coefficient in the equation.
(0.15 mol KO₂)/4 = 0.0375
(0.10 mol H₂O)/2 = 0.05
KO₂ is the limiting reagent.
The amount of product produced depends on the limiting reagent. To find how much is produced, take moles of limiting reagent and multiply it by the ratio of reagent to product. You can find the ratio by looking at the equation. For every 4 moles of KO₂, 3 moles of O₂ are produced.
0.15 mol KO₂ (3 mol O₂)/(4 mol KO₂) = 0.1125 mol O₂
0.11 mol O are produced.
In simple diffusion, small molecules without charges such as oxygen and carbon dioxide flow through a plasma membrane without assistance and without expending energy. Other substances such as proteins<span>, glucose and charged particles called ions cannot pass through the selectively permeable membrane.</span>
Answer: 
: Pure substance, Element
: Pure substance , Element
: Pure substance, Compound
Explanation:
Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: 
and
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example:
Heterogeneous Mixture : Mixture that has its different components mixed unevenly within the substance
. Example: Air
Homogeneous Mixture : Mixture that has its different components mixed evenly within the substance. Example: sugar dissolved in water
Answer:
Balance chemical equation is
O2(g) + 2H2(g) --> 2H20(g)
a. 0.20 mol 02 --> 0.225mol H20
b. 0.30 mol H2 --> 2.7mol H20
