Consider a sealed glass bottle. If the bottle is thrown into a fire, what will happen to the bottle and why? Which law is the be
1 answer:
You might be interested in
Answer:
1) The solubility product of the lead(II) chloride is .
2) The solubility of the aluminium hydroxide is .
3)The given statement is false.
Explanation:
1)
Solubility of lead chloride =
S 2S
The solubility product of the lead(II) chloride =
The solubility product of the lead(II) chloride is .
2)
Concentration of aluminium nitrate = 0.000010 M
Concentration of aluminum ion =
Solubility of aluminium hydroxide in aluminum nitrate solution =
S 3S
The solubility product of the aluminium nitrate =
The solubility of the aluminium hydroxide is .
3.
Mass of NaCl= 3.5 mg = 0.0035 g
1 mg = 0.001 g
Moles of NaCl =
Volume of the solution = 0.250 L
1 mole of NaCl gives 1 mole of sodium ion and 1 mole of chloride ions.
Moles of lead (II) nitrate = n
Volume of the solution = 0.250 L
Molarity lead(II) nitrate = 0.12 M
1 mole of lead nitrate gives 1 mole of lead (II) ion and 2 moles of nitrate ions.
Solubility of lead(II) chloride =
Ionic product of the lead chloride in solution :
( no precipitation)
The given statement is false.
<u>Answer:</u> The molality of solution is 0.740 m.
<u>Explanation:</u>
To calculate the mass of solvent (water), we use the equation:
Volume of water = 750 mL
Density of water = 1 g/mL
Putting values in above equation, we get:
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute
= 100.0 g
= Molar mass of solute
= 180 g/mol
= Mass of solvent (water) = 750 g
Putting values in above equation, we get:
Hence, the molality of solution is 0.740 m.