The visible wavelengths constructively reflected by the film when it is surrounded by air on both sides can be calculated using the equation:
lambda = 2t*(n2/n1)
where:
lambda is the wavelength,
t is the thickness, and;
n1 and n2 are indexes of refraction
The answer would be Power
Answer:
100 foot
Explanation:
Using the formula for calculating range to calculate the speed first as shown;
<h3>Range R = U²sin 2theta/g</h3>
U is the speed
theta is the observe angle
g is the acceleration due to gravity.
200 = U²sin 2(45)/9.8
Usin90 = 200 * 9.8
U² = 1960
U = √1960
U = 44.27 m/s
Get the required altitude
Altitude H = u²/2g
H = 44.27²/2(9.8)
H = 1,959.8329/19.6
<em>H = 99.99 feet</em>
<em>Hence the altitude of the rocket to the nearest foot is 100 foot</em>
Answer:
1143 N at 1.59 m from the left end
Explanation:
For the system to produce equilibrium, the total force and moment must be 0. Since the total weight downward is
481 + 381 + 281 = 1143 N
Therefore the magnitude of the force acting upward to balance this system must be the same of 1143 N
That alone is not enough, we also need the position of the force for the total moment to be 0.
Let x be the length from the this upward force to the left side. And let the left point be the point of reference for moment arm:
481 * 3.32/2 + 381 * 0.8798 + 281*(3.32 - 0.8798) - 1143*x = 0
x = (481*1.66 + 381 * 0.8798 + 281*2.4402)/1143 = 1.59m
East is our x axis
north is out y axis N
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W _____|_______E
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S
so he moves 3 m to the right and then 4 upwards
imagine what that looks like.......... a right angle triangle
therefore we can use Pythagorean theorem
let the unknown side be x, which is the hypotenuse in this case
x^2 = 3^2 + 4^2
x^2 = 9 + 16
x^2 = 25
take the square root
x = 5
5 is your magnitude and the direction is NE( North East) or positive direction
