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Semenov [28]
2 years ago
7

What is the velocity of a wave with a wavelength of 3.7 m and a frequency of 22.5 Hz?

Physics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer: 343 m/s. The sound wave has a frequency of. 436 Hz. What is the period of the wave? T = = 436 Hz. = 2.29x10-3 s. C. What is the wave's wavelength? To halve

Explanation:

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Instructions:Select all the correct answers.
melomori [17]
The answer would be B: The ground exerts an equal force on the golf ball.
6 0
3 years ago
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which of the following are vector quantities? check all that apply. a. time b. displacement c. force d. mass
AveGali [126]
All except d. mass .........
8 0
3 years ago
Write a linear equation that expresses the relationship between the temperature in degrees Celsius (C) and degrees Fahrenheit (F
UkoKoshka [18]

Answer:

\displaystyle F=\frac{9}{5}C+32

\displaystyle C=\frac{5}{9}(F-32)

Explanation:

<u>Temperature Units Conversion </u>

The conversion formula between Celsius and Fahrenheit temperature scales is well-known. But we'll use the provided data to derive the formula. Let's model the relationship between Fahrenheit (F) and Celsius (C) as a linear function like

F=mC+b

Where m and b must be computed according to the pair of conditions given. The values for each temperature scale are (C,F)=(0,32) and (100,212). Replacing the first value

32=m\times 0+b

It means that  

b=32

By using the second point

212=m\times 100+32

Solving for m

\displaystyle m=\frac{212-32}{100}=\frac{180}{100}

Simplifying

\displaystyle m=\frac{9}{5}

So, the conversion formula is

\displaystyle F=\frac{9}{5}C+32

Which is the widely known formula for temperature conversion

Solving for C, we get the inverse relation

\boxed{\displaystyle C=\frac{5}{9}(F-32)}

3 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
2 years ago
What is the density of a 15g block of metal with a volume of 2cm3?
JulsSmile [24]

Answer:

density =mass/volume

Explanation:

density=15/2

density=7.5 g/cm³

4 0
3 years ago
Read 2 more answers
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