What is the most common way atoms combine

What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?

garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

$M=\frac{4.4mol}{1.5L} =2.9 M$

7 0

3 years ago

WILL MARK BRAINLIST

Free_Kalibri [48]

Answer:

The average speed must be 30mph so this means the car traveled for 2hrs 60/30

7 0

3 years ago

A student designs an experiment to see the effects exposing a block of ice to sunlight over time. The students makes a hypothesi

jeka94

In this experiment, the experimental group is ice, the independent variable is sunlight while on the other hand, the dependent variable is block of ice.

<h3>What are dependent and independent variables?</h3>

Dependent variable is a type of variable in which a variable whose value depends on another variable while on the other hand, independent variable is a type of variable in which a variable whose value does not depends on another variable. Dependent variable is denoted by X whereas the independent variable is denoted by Y.

So we can conclude that In this experiment, the experimental group is ice, the independent variable is sunlight while on the other hand, the dependent variable is block of ice.

Learn more about variable here: brainly.com/question/25223322

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8 0

2 years ago

You have two solid substances that look the same. What measurements would you take and which tests would you preform to determin

ASHA 777 [7]

Answer:

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5 0

2 years ago

Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(

likoan [24]

Balanced Half reactions are:

At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

Now at Anode reaction will occur as given:

2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

At Cathode:

2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

At Cathode:

$Mn^{2+}$ + $2e^{-}$ ==> Mn (This reaction will not occur)

The deposition of solid Mn will not occur because in aqueous solution, $H^{+}$ will be reduced before $Mn^{2+}$ .

The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

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8 0

2 years ago