M(NaCl)=50.0 g
m(H₂O)=150.0 g
m(solution)=m(NaCl)+m(H₂O)
w(NaCl)=100m(NaCl)/m(solution)=100m(NaCl)/{m(NaCl)+m(H₂O)}
w(NaCl)=100*50.0/(50.0+150.0)=25%
Answer:
aldehyde
Explanation:
Aldehydes are a large class of reactive organic compounds (R-CHO) having a carbonyl functional group attached to one hydrocarbon radical and a hydrogen atom.
So, when terminal alkynes, for example, 1-heptyne react on Hydroboration oxidation(i.e. disiamylborane followed by treatment with basic hydrogen peroxide), the formation of aldehyde occurs.
Answer:
I'm not 100% sure but I think it is b I'm not great with math tho
In nickel-78, there are 28 protons, 28 electrons, and 50 neutrons.
The protons is always the atomic number.
The electron would always be the atomic number when it's a neutral atom. (Different for isotopes)
The neutrons is always the number that makes up the mass with protons. You can figure it out by subtracting atomic mass by protons. (78-28 = 50)