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just olya [345]
3 years ago
13

The earth takes 1 year to revolve around the sun at 1 A.U. distance (an astronomical unit = 93,000,000 miles). If a planet were

4 A.U. from the sun, how many years would it take to make 1 orbit?
Physics
1 answer:
inessss [21]3 years ago
4 0
Kepler's third law states that the square of the orbital period is proportional to the cube of the semi-major axis of its orbit. In equation form, P^2 / a^3 = constant. For the earth, (1 y)^2 / (1 AU)^3 = 1, so the constant is 1. For a planet 4 AU from the sun:
P^2 / (4 AU)^3 = 1P^2 = 64P = 8 years

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Karen runs sets in basketball practice. She starts from a line runs 2.0 m, returns to the line, runs 4.0 m, to the line, runs 6.
Aleonysh [2.5K]

D. distance = 23 m, displacement = + 1 m

Explanation:

Let's remind the difference between distance and displacement:

- distance is a scalar, and is the total length covered by an object, counting all the movements in any direction

- displacement is a vector connecting the starting point and the final point of a motion, so its magnitude is given by the length of this vector, and its direction is given by the direction of this vector.

In this case, the distance covered by Karen is given by the sum of all its movements:

distance = 2.0 m + 2.0 m+4.0 m+4.0 m +6.0 + 5.0 m=23.0 m

The displacement instead is given by the difference between the final point (1.0 m in front of the starting line) and the starting point (the starting line, 0 m):

displacement = +1.0 m-0 m=+1 m

8 0
3 years ago
. Write the following in the scientific notation of 0.0000002400m ​
aleksandr82 [10.1K]

Explanation:

<h2><u>Steps </u><u>:</u></h2>
  1. <u>Move </u><u>decimal</u><u> </u><u>from</u><u> </u><u>left </u><u>to </u><u>right</u><u> </u><u>=</u><u>0</u><u> </u><u>0</u><u>0</u><u>0</u><u>0</u><u>0</u><u>0</u><u>2</u><u>4</u><u>0</u><u>.</u><u>0</u>
  2. <u>Then </u><u>count </u><u>the</u><u> </u><u>numbers</u><u> </u><u>before</u><u> </u><u>decimal </u><u>and </u><u>w</u><u>rite </u><u>it </u><u>like</u><u> </u><u>this </u><u>=</u><u>2</u><u>4</u><u>0</u><u>.</u><u>0</u><u>x</u><u>1</u><u>0</u><u> </u><u>power-</u><u>9</u><u> </u>
  3. <u>That's</u><u> </u><u>all </u>

<u>hope</u><u> it</u><u> </u><u>help</u>

<h2><u>#</u><u>H</u><u>o</u><u>p</u><u>e</u></h2>
7 0
2 years ago
The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
Sholpan [36]

The frequency of rotation of Mars is 0.0000113 Hertz.

<u>Given the following data:</u>

  • Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

<u>Conversion:</u>

1 day = 24 hours

24 hours to minutes = 60 × 24 = 1440 minutes

1440 + 37 = 1477 \; minutes

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

X = 60 × 1477

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}

<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: brainly.com/question/14708169

8 0
2 years ago
A child on a bridge throws a rock straight down to the water below. The point where the child released the rock is 82 m above th
eimsori [14]

Answer:

40 m/s

Explanation:

given,

height of the fall, h = 82 m

time taken to fall, t = 1.3 s

rock velocity, v = ?

acceleration due to gravity, g = 9.8 m/s²

rock is released initial velocity, u = 0 m/s

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 x 9.8 x 82

v² = 1607.2

v = 40 m/s

hence, rock's velocity is equal to 40 m/s

6 0
2 years ago
Radio waves travel at a speed of 300,000,000 m/s. WFNX broadcasts radio waves at a
yKpoI14uk [10]

Answer:

Wavelength, \lambda=2.94\ m

Explanation:

It is given that,

Speed of radio waves is v=3\times 10^8\ m/s

Frequency of radio waves is f = 101,700,000 Hz

We need to find the wavelength of WFNX’s radio waves. The relation between wavelength, frequency and speed of a wave is given by :

v=f\lambda

\lambda is wavelength

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{3\times 10^8}{101,700,000}\\\\\lambda=2.94\ m

So, the wavelength of WFNX’s radio waves is 2.94 m.

3 0
3 years ago
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