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Tema [17]
3 years ago
6

Write the following number in scientific notation: 658000

Physics
1 answer:
Mice21 [21]3 years ago
8 0
6.58 x 105 is the answer
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HELP...<br> 3.00 amu = _____ Mev.<br><br> 3.22 x 10-3<br> 2.79 x 103<br> 3.10 x 102
DanielleElmas [232]
The correct answer is:
2.79 \cdot 10^3 MeV
Let's see why.

1 amu corresponds to the mass of the proton, which is:
m_p = 1.66 \cdot 10^{-27} kg
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
E=mc^2 = (1.66 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2 = 1.49 \cdot 10^{-10} J
Now we can convert it into electronvolts:
E= \frac{1.49 \cdot 10^{-10}kg}{1.6 \cdot 10^{-19} J/eV} =9.34 \cdot 10^9 eV = 934 MeV

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
3 amu = 3 \cdot 934 MeV  \sim 2790 MeV = 2.79 \cdot 10^3 MeV
5 0
3 years ago
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Which of the following would decrease the magnetic field around a wire?
shusha [124]
The correct answer is
<span>A. decreasing the current

In fact, the magnetic field produced by a current carrying wire is given by
</span>B(r) =  \frac{\mu_0 I}{2 \pi r}
<span>where
</span>\mu_0 is the vacuum permeability
<span>I is the current in the wire
r is the distance from the wire at which the field is calculated

We see from the formula that the intensity of the field, B, is directly proportional to the current I, so if the current decreases, the magnetic field strength B decreases as well.</span>
4 0
3 years ago
Which trail is it? Answer!
Pepsi [2]
Wouldn’t it be 1. resistance is high compared to the voltage and with less resistance, higher current
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2 years ago
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What is the reason eclipses do not happen every full moon and new moon
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6 0
2 years ago
Two equally charged insulating balls each weigh 0.16 g and hang from a common point by identical threads 35 cm long. The balls r
Dafna11 [192]

Answer:

Q₁ = Q₂ = 8.84 x 10⁻⁹ C

Explanation:

given,

mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg

ball each other, r = 6.8 cm

Weight of the ball

F_w = m g

F_w = 1.6 x 10⁻⁴ x 9.8

F_w = 1.56 x 10⁻³ N

The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.

we have to find the horizontal component of the forces.

The length of the string,L is 35 cm so, it will be the hypotenuse.

θ be the angle made with imaginary vertical line and the string.

now,

sin \theta = \dfrac{r\2}{L}

sin \theta = \dfrac{3.4}{35}

   θ = 5.57°

horizontal component of the force = ?

vertical component of force,F_v = 1.56 x 10⁻³ N

tan\theta = \dfrac{F_H}{F_v}

tan(5.57^0) = \dfrac{F_H}{1.56\times 10^{-3}}

 F_h = 1.52 x 10⁻⁴ N

now, each ball will be repelled by

F = 1.52 x 10⁻⁴ N

now calculation of charges

F = \dfrac{kQ_1Q_2}{r^2}

Q₁ = Q₂ because both charge are same

1.52\times 10^{-4} = \dfrac{9\times10^9Q^2}{0.068^2}

    Q² = 7.809 x 10⁻¹⁷

   Q = 8.84 x 10⁻⁹ C

hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C

5 0
3 years ago
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