Question

Young's double slit experiment is one of the classic tests for the wave nature of light. In an experiment using red light (λ = 641 nm) the second dark fringe on either side of the central maximum is θ = 4.4 degrees relative to the central bright fringe.
(a) Write an expression for the separation distance between the slits.

Answer 1

Answer:

The separation distance between the slits is 16710.32 nm.

Explanation:

Given that,

Wavelength = 641 nm

Angle =4.4°

(a). We need to calculate the separation distance between the slits

Using formula of young's double slit

$d\sin\theta=m\lambda$

$d=\dfrac{m\lambda}{\sin\theta}$

Where, d = the separation distance between the slits

m = number of order

$\lambda$ =wavelength

Put the value into the formula

$d=\dfrac{2\times641\times10^{-9}}{\sin4.4}$

$d=0.00001671032\ m$

$d=16710.32\ nm$

Hence, The separation distance between the slits is 16710.32 nm.